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galben [10]
3 years ago
12

Roberto, Christopher, and Joe are amateur cyclist riding in the 165.1 km long  Tour of Cortez bicycle race. Each cyclist is indi

vidually timed in the event.
Two hours into his race, Roberto has completed 73.4 km.

Three hours into his race, Christopher has completed 112.6 km.

Three and a half hours into his race, Joe has completed 128.2 km.

The cyclist must complete the race in under 260 minutes to qualify for the professional cyclist series for the upcoming year.

Place the cyclist in order from the least average minutes per km to the greatest average minutes per km that they need ride for the remainder of the race to qualify for the professional cyclist series.
Mathematics
1 answer:
neonofarm [45]3 years ago
5 0
Roberto: 2 hours equals 160 minutes. 73.4 km ÷ 160 min = 0.45875

Christopher: 3 hours equals 180 minutes. 112.6 km ÷ 180 min = 0.6255555556

Joe: 3.5 hours equals 210 minutes. 128.2 km ÷ 210 min = 0.6104761905


List from least to greatest:
1. Roberto
2. Joe
3. Christopher
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The shadow of the tree is about 17.955 feet long.
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2 years ago
Un auto viaja con una velocidad promedio de 84 kilómetros por hora. ¿En cuánto tiempo viaja 462 kilómetros?
timama [110]

The car takes the time 5.5 hours i.e.5 hours and 30 minutes to travel 462 kilometres when the car travels at average speed of 84 kilometres per hour

Given the average speed of the car is 84 kilometres per hour and the distance to be travelled is 462 kilometres and asked to find the time taken for the journey of 462 kilometres

To calculate the time taken for the journey we use the below-mentioned formula

speed=\frac{distance}{Time taken}

(speed)×(Time taken)=distance

Time taken=\frac{distance}{speed}

Time taken=\frac{462 kilometres}{84KMPH}

Time taken=5.5 hours i.e.5 hours and 30 minutes

As a result, the time spent on the car journey is 5.5 hours

Hence, It takes the time 5hours and 5 minutes to travel 462 kilometres

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5 0
1 year ago
The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a
liubo4ka [24]

Answer:

(x,y,z)=(1477, 1464, 1437)

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>
  • Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
  • Mr.A earns Rs6000

So, the equation would be

3x  +  5y - 4z = 6000

<h3>Case-2:</h3>
  • Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
  • Mr B neither lose nor gain meaning he has made 0₹

hence,

2x   - 3y  +  z = 0

<h3>Case-3:</h3>
  • Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
  • Mr.C earns 13000₹

therefore,

- x    + 4y  +  6z = 13000

Thus our system of equations is

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\end{cases}\\\begin{cases}2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

Now solve the equation accordingly:

\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}

Solving the equation for x and y yields:

\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

\implies z= \dfrac{217000}{151}

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

6 0
2 years ago
The nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium. To determine if the
lora16 [44]

Answer:

We conclude that the sodium content is same as what the nutrition label states.

Step-by-step explanation:

We are given that the nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium.

The FDA randomly selects 40 packages of Oriental Spice Sauce and determines the sodium content. The sample has an average of 1088.64 milligrams of sodium per package with a sample standard deviation of 234.12 milligrams.

<u><em /></u>

<u><em>Let </em></u>\mu<u><em> = average sodium content.</em></u>

So, Null Hypothesis, H_0 : \mu = 1100 milligrams      {means that the sodium content is same as what the nutrition label states}

Alternate Hypothesis, H_A : \mu \neq 1100 milligrams      {means that the sodium content is different from what the nutrition label states}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                    T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}  ~ t_n_-_1

where, \bar X = sample average sodium content = 1088.64 milligrams

            s = sample standard deviation = 234.12 milligrams

            n = sample of packages of Oriental Spice Sauce = 40

So, <u><em>test statistics</em></u>  =  \frac{1088.64-1100}{\frac{234.12}{\sqrt{40}}}  ~ t_3_9

                              =  -0.307

The value of z test statistics is -0.307.

<em>Since, in the question we are not given the level of significance so we assume it to be 5%. </em><em>Now, at 0.05 significance level the t table gives critical values of -2.0225 and 2.0225 at 39 degree of freedom for two-tailed test.</em><em> </em>

<em>Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the sodium content is same as what the nutrition label states.

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3 years ago
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