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DiKsa [7]
3 years ago
13

A school director Must randomly select 6 teachers to participate in a training session there are 30 teachers at the school in ho

w many different ways can these teachers be selected if the order of selection does not matter
Mathematics
1 answer:
Ede4ka [16]3 years ago
7 0

Solution:

we are given that

A school director Must randomly select 6 teachers to participate in a training session there are 30 teachers at the schoo. The order of selection does not matter.

As we know

6 teacheras can be selected out of 30 teacher in {30}_C_6 ways.

{30}_C_6=\frac{30!}{6!24!}\\
\\  {30}_C_6=\frac{25*26*27*28*29*30}{1*2*3*4*5*6}\\
\\  {30}_C_6=593775

Hence the required number of ways is 593775.

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Some help me please help me please help me please
kodGreya [7K]
1_ 210+90= 300



2_ it's prime:


[1,19]




good luck


4 0
3 years ago
9 x 10 to the power of 2 how many times as much as 3 x 10 to the -2 power
hjlf

Answer:

  3×10^4

Step-by-step explanation:

The desired factor is found by calculating the ratio of the two numbers:

  k = (9×10^2)/(3×10^-2) = (9/3)×10^(2 -(-2)) = 3×10^4

The first number is 3×10^4 = 30,000 times as much as the second number.

6 0
2 years ago
Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively. How many times will t
Evgen [1.6K]

Answer:

60 times will they ring together at the same second in one hour excluding the one at the end.

Step-by-step explanation:

Given : Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively.

To find : How many times will they ring together at the same second in one hour excluding the one at the end?

Solution :

First we find the LCM of 3, 6, 10, 12 and 15.

2 | 3  6  10  12  15

2 | 3  3   5   6  15

3 | 3  3   5   3  15

5 | 1    1  5   1    5

  | 1    1   1   1     1

LCM(3, 6, 10, 12,15)=2\times 2\times 3\times 5

LCM(3, 6, 10, 12,15)=60

So, the bells will ring together after every 60 seconds i.e. 1 minutes.

i.e. in 1 minute they rand together 1 time.

We know, 1 hour = 60 minutes

So, in 60 minute they rang together 60 times.

Therefore, 60 times will they ring together at the same second in one hour excluding the one at the end.

6 0
3 years ago
I want to see if your are smart and tell me what the answer is <br><br>50-(14+12+2(5)+2(2)+3
Solnce55 [7]
The answer is 7. If you follow the order of PEMDAS this is an easy question.
7 0
3 years ago
Plz help me well mark brainliest!..
Sav [38]

Answer:

(-2, -4.5) is the answer!

I hope this helps!

5 0
3 years ago
Read 2 more answers
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