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3 years ago

Choose the abbreviation of the postulate or theorem that supports the conclusion that WAS NOT.

2 answers:

5 0

Hello.

The asnwer is ASA -

If two angles and the included side are equal to two angles and the included side of another triangle.

Have a nice day

Pie3 years ago

3 0

Answer:

The answer is SAS. I am positive. I just had my answer graded.

Step-by-step explanation:

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svetoff [14.1K]

A convex polygon
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3 years ago

Please solve this question fast.

Alexxandr [17]

Answer:

See Explanation

Step-by-step explanation:

${a} = {6}^{x}, \: \: b = {6}^{y} ...(given) \\ {a}^{y}. {b}^{x} = 36..(1) \\ pluggig \: the \: values \: of \: a \: and \: b \: in \: (1) \\ ({6}^{x}) ^{y} . ({6}^{y}) ^{x} = {6}^{2} \\ {6}^{xy}.{6}^{xy} = {6}^{2} \\ {6}^{xy + xy} = {6}^{2} \\ {6}^{2xy} = {6}^{2} \\ bases \: are \: equal \: so \: exponentes \: will \: also \: be\\ \: equal \\ \therefore \: 2xy = 2 \\ xy = \frac{2}{2} \\ \huge \red { \boxed{ xy = 1}} \\ hence \: proved \\$

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2 years ago

What is the area of the parallelogram?

slega [8]

Answer:

A=Bh

Step-by-step explanation:

use that formula for your calculation and it should help hopefully

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2 years ago

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charle [14.2K]

Answer:

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Step-by-step explanation:

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3 years ago

The probability that Jane will go to a ballgame (event A) on a Monday is 0.73, and the probability that Kate will go to a ballga

sergiy2304 [10]

Answer:

dependent events since P(A and B) is not equal to P(A) * P(B)

Step-by-step explanation:

According to the Question,

Given, The probability that Jane will go to a ballgame (event A) on a Monday is 0.73, and the probability that Kate will go to a ballgame (event B) the same day is 0.61. The probability that Kate and Jane both go to the ballgame on Monday is 0.52.

Thus, The events A, B and A∩B are:

A - Jane will go to a ballgame on Monday;

B - Kate will go to a ballgame on Monday;

A∩B - Kate and Jane both go to the ballgame on Monday.

P(A)=0.73, P(B)=0.61, P(A∩B)=0.52.

Pr(A)⋅Pr(B) = 0.73⋅0.61 = 0.4453 ≠ 0.52

So, events A and B are dependent events since P(A and B) is not equal to P(A) * P(B)

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3 years ago