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taurus [48]
3 years ago
7

Use the law of syllogism to form a conclusion from the given premises. Premise 1: If a polygon was translated to the right, then

its image is congruent to its pre-image. Premise 2: If an image is congruent to its pre-image, then a rigid transformation was performed. Select from the drop-down menus to correctly complete the conclusion.
Mathematics
2 answers:
Setler [38]3 years ago
8 0

<u><em>Ok You're probably here from K12 so heres the answer:</em></u>

Conclusion: If a polygon undergoes a rigid transformation, then the image and pre-image have equal perimeters.

<em><u>I just took the test and got this right, I'm a K12 student as well. </u></em>

<u><em>Hope this helps :)</em></u>

Pachacha [2.7K]3 years ago
3 0
<span>Premise 1: If a polygon was translated to the right, then its image is congruent to its pre-image.

In symbols: p => q

Premise 2: If an image is congruent to its pre-image, then a rigid transformation was performed.

In symbols: q => r

By the law of silogism

(p => q) and (q => r) => q => r

So, the conclusion is that </span><span>if a polygon was translated to the right, then a rigid transformation was performed. <---- answer</span>
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6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each
umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em />n = 35<em> --- the number of lines</em>

<em />d = 3<em> --- no three lines are concurrent</em>

<em />

When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

  • <em>0 intersection for 1 line</em>
  • <em>1 intersection for 2 lines</em>
  • <em>3 intersections for 3 lines</em>
  • <em>6 intersections for 4 lines</em>

<em />

Following the above sequence, the number of intersections for n lines is:

n_k = \frac{n \times (n - 1)}{2}

In this case, n = 35.

So, we have:

n_k = \frac{35 \times (35 - 1)}{2}

n_k = \frac{35 \times 34}{2}

n_k = 35 \times 17

n_k = 595

<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

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Read more about lines of intersections at:

brainly.com/question/22368617

7 0
3 years ago
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marshall took $36.75 to a fair. Each ticket into the fair costs X dollars. marshall bought 3 tickets. which expression represent
Sholpan [36]
Y = money left over
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Y = 36.75 - 3x
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3 years ago
Angie and Kenny play online video games. Angie buys 1 software package and 2 months of game play. Kenny buys 1 software package
GalinKa [24]

Answer:

The cost of one month of game​ play is $12.    

Step-by-step explanation:

We are given the following in the question:

Cost of software package = $30

Let y dollars be the cost of one month of game play.

Angie buys 1 software package and 2 months of game play.

Angie's cost =

1(30) + 2y = 2y + 30

Kenny buys 1 software package and 4 months of game play.

Kenny's cost =

1(30) + 4y = 4y + 30

Total cost = $132​

Thus, we can write the equation:

(2y+30)+(4y+30) = 132\\6y + 60 = 132\\6y = 132-60\\6y = 72\\\Rightarrow y = 12

Thus, the cost of one month of game​ play is $12.

7 0
3 years ago
How many solutions are there to the equation below 8x + 11 = 8x + 8
Nataly [62]

8x + 11= 8x + 8

8x - 8x = 8 - 11

0 = - 3 False


No solutions.

Answer is B.0.

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Evaluate the determinant of the matrix.<br> -4 5 6<br> 0 4 4<br> -2 -5 4<br> I need the work plz
FromTheMoon [43]

Answer:

-136

Step-by-step explanation:

We have to find the determinant of the following matrix:

\left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]

We can find the determinant by expanding via 1st column. i.e. by taking each element of 1st column and multiplying it by its co-factor matrix as shown below:

det \left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]

= (-4 \times det \left[\begin{array}{cc}4&4\\-5&4\end{array}\right]) - (0 \times (-4 \times det \left[\begin{array}{cc}5&6\\-5&4\end{array}\right]))+ ((-2) \times det\left[\begin{array}{cc}5&6\\4&4\end{array}\right])\\\\ =-4 \times (16 + 20)-(0)+(-2 \times 20-24)\\\\ =-4(36)+(-2(-4))\\\\ =-144+8\\\\ =-136

The notation det() stands for determinant of the matrix.

Therefore, the determinant of the given matrix is -136

8 0
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