The point of intersection is the point where lines intersect.
<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>
<em />
Given
<em />
<em> --- the number of lines</em>
<em />
<em> --- no three lines are concurrent</em>
<em />
When no three line are concurrent, it means that no three lines meet at the same point.
<u>So, the sequence of intersection is:</u>
- <em>0 intersection for 1 line</em>
- <em>1 intersection for 2 lines</em>
- <em>3 intersections for 3 lines</em>
- <em>6 intersections for 4 lines</em>
<em />
Following the above sequence, the number of intersections for n lines is:

In this case, 
So, we have:




<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>
<em />
Read more about lines of intersections at:
brainly.com/question/22368617
Y = money left over
X = fair ticket
Y = 36.75 - 3x
Answer:
The cost of one month of game play is $12.
Step-by-step explanation:
We are given the following in the question:
Cost of software package = $30
Let y dollars be the cost of one month of game play.
Angie buys 1 software package and 2 months of game play.
Angie's cost =

Kenny buys 1 software package and 4 months of game play.
Kenny's cost =

Total cost = $132
Thus, we can write the equation:

Thus, the cost of one month of game play is $12.
Answer:
-136
Step-by-step explanation:
We have to find the determinant of the following matrix:
![\left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%265%266%5C%5C0%264%264%5C%5C-2%26-5%264%5Cend%7Barray%7D%5Cright%5D)
We can find the determinant by expanding via 1st column. i.e. by taking each element of 1st column and multiplying it by its co-factor matrix as shown below:
det ![\left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%265%266%5C%5C0%264%264%5C%5C-2%26-5%264%5Cend%7Barray%7D%5Cright%5D)
= ![(-4 \times det \left[\begin{array}{cc}4&4\\-5&4\end{array}\right]) - (0 \times (-4 \times det \left[\begin{array}{cc}5&6\\-5&4\end{array}\right]))+ ((-2) \times det\left[\begin{array}{cc}5&6\\4&4\end{array}\right])\\\\ =-4 \times (16 + 20)-(0)+(-2 \times 20-24)\\\\ =-4(36)+(-2(-4))\\\\ =-144+8\\\\ =-136](https://tex.z-dn.net/?f=%28-4%20%5Ctimes%20det%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%264%5C%5C-5%264%5Cend%7Barray%7D%5Cright%5D%29%20-%20%280%20%5Ctimes%20%28-4%20%5Ctimes%20det%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%266%5C%5C-5%264%5Cend%7Barray%7D%5Cright%5D%29%29%2B%20%28%28-2%29%20%5Ctimes%20det%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%266%5C%5C4%264%5Cend%7Barray%7D%5Cright%5D%29%5C%5C%5C%5C%20%3D-4%20%5Ctimes%20%2816%20%2B%2020%29-%280%29%2B%28-2%20%5Ctimes%2020-24%29%5C%5C%5C%5C%20%3D-4%2836%29%2B%28-2%28-4%29%29%5C%5C%5C%5C%20%3D-144%2B8%5C%5C%5C%5C%20%3D-136)
The notation det() stands for determinant of the matrix.
Therefore, the determinant of the given matrix is -136