1. 4 1/5
2. 11/24
3. 12 1/4
4. 2
5. 3 5/12
I did the math but I’m sorry if it’s not all correct
Answer:
302yrs old.... DAM
Step-by-step explanation:
2x-400=204
+400 +400
2x=604
/2 /2
x=302
the asnwer is 14 feet 5 inches because you add feet and then inches
Answer: A
Step-by-step explanation: -2 is your y-int and if you do your rise over run it’s -1/2
Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
