The angles inside a triangle add up to 180°
The 3rd angle is supplementary to (6x+1)°
Supplementary means they make a straight line (i.e 180°)
1st angle = 79°
2nd angle = (2x+10)°
3rd angle = 180° - (6x+1)°
180 = 79 + (2x+10) + 180 - (6x+1)
180 = 79 + 2x + 10 + 180 - 6x - 1
combine like terms
180 - 180 - 79 - 10 + 1 = 2x - 6x
-88 = -4x
-88/-4 = x
22 = x
According to my calculations,
A. is the correct answer.
8√5
If the arc measures 250 degrees then the range of the central angle lies from π to 1.39π.
Given that the arc of a circle measures 250 degrees.
We are required to find the range of the central angle.
Range of a variable exhibits the lower value and highest value in which the value of particular variable exists. It can be find of a function.
We have 250 degrees which belongs to the third quadrant.
If 2π=360
x=250
x=250*2π/360
=1.39 π radians
Then the radian measure of the central angle is 1.39π radians.
Hence if the arc measures 250 degrees then the range of the central angle lies from π to 1.39π.
Learn more about range at brainly.com/question/26098895
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Answer: Order will be F,D,C and Fourth Option is correct and x = 10
Step-by-step explanation:
Since we have given that
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We first transpose the square root to the right , so it becomes square of 8,i.e.

Now, transpose 4 to the right so it will get subtract from 64 i.e.

Since 6 is multiplied to x on tranposing it will get divided by 60 i.e.

Hence, on simplification, we get x=10.
Hence , the order is F,D,C.
Lets go step by step and factor out each as we go
first lets factor out a 3 since 3 is common in 9 and 3
3(3ab^2 - abc)
now lets factor out a since its common in both
3a(3b^2 - bc)
now lets factor out a b since its common in both
3ab(b - c)
we can't factor anything else out so we are done.