If you roll 2 dice, what is the probability that the sum is 9?

Mathematics

1 answer:

Allushta [10]2 years ago

6 0

Answer:

0.1111%

Step-by-step explanation:

2 dice, each with 6 sides. 36 possible outcomes.

Possible sums for 9 are 1,8 2,7 3,6 4,5

That means there is only 4 possible ways to get 9 out of 36 possible outcomes. 4/36 is your probability

You might be interested in

What’s the answer for this?

Yuliya22 [10]

Answer:

1.98

Step-by-step explanation:

sin(26) = EF/4.5 -->

.44 = EF/4.5 -->

.44 * 4.5 = EF -->

1.98 = EF

5 0

2 years ago

What is 1 10/50 improper

Karolina [17]

Answer:

$1 \frac{10}{50} = \frac{60}{50}$

5 0

3 years ago

How do you simplify this expression step by step?

nataly862011 [7]

$\bf \textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{csc(\theta )-sin(\theta )}{cos(\theta )}\implies \cfrac{~~\frac{1}{sin(\theta )}-sin(\theta )~~}{cos(\theta )}\implies \cfrac{~~\frac{1-sin^2(\theta )}{sin(\theta )}~~}{cos(\theta )}$

$\bf \cfrac{1-sin^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{cos(\theta )}\implies \cfrac{\stackrel{cos(\theta )}{\begin{matrix} cos^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}} }{sin(\theta )}\cdot \cfrac{1}{\begin{matrix} cos(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }\implies \cfrac{cos(\theta )}{sin(\theta )}\implies cot(\theta )$