All categories

2 years ago

PLEASE HELP!! ILL GIVE BRAINLIEST!!

Mathematics

1 answer:

torisob [31]2 years ago

3 0

Step-by-step explanation:

C. yes sure qamar would have a lacquer to cover it .

D. justice League of the mathematical model..

E.she needs about 45ft

You might be interested in

What part of 12 is 3?

Butoxors [25]

Fourth part of 12 is 3

3 0

3 years ago

7x +2y = 24 8x+2y= 30 What is x and y

Liula [17]

Answer:

x = 6

y = -9

Step-by-step explanation:

we have:

7x +2y = 24 equation 1

8x+2y= 30 equation 2

using equation 2 we have:

8x = 30 -2y

x= $\frac{30-2y}{8}$ equation 3

using equation 3 in equation 1 we have:

7( $\frac{30-2y}{8}$ )+2y = 24

$\frac{210}{8} - \frac{14y}{8} +2y =24\\\\\frac{1}{4}y = -\frac{18}{8} \\\\y=-\frac{18}{8} * 4\\\\y=-9$

so we have:

x= $\frac{30-2(-9)}{8}$

x= $\frac{30+18}{8}$

x=6

7 0

3 years ago

Read 2 more answers

Can someone please help me ASAP❤️

Eddi Din [679]

38,320 (for positive scientific notation you move the decimal to the right how ever many places, so move the decimal 4 places to the right in this case)

4 0

3 years ago

The z-score associated with 95% is 1.96. If the sample mean is 200 and the standard deviation is 30, find the upper limit of the

ziro4ka [17]

Answer:

The upper limit of the 95% confidence interval is:

C.I_u = 200 + (58.8/ $\sqrt{n}$ )

Step-by-step explanation:

The formula is given as:

C.I = μ ± Z*σ/ $\sqrt{n}$

The upper limit => C.I_u = μ + Z*σ/ $\sqrt{n}$

The lower limit => C.I_l = μ - Z*σ/ $\sqrt{n}$

The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.

The upper limit => C.I_u = 200 + 1.96*(30/ $\sqrt{n}$ )

= 200 + (1.96*30)/ $\sqrt{n}$

= 200 + 58.8/ $\sqrt{n}$

5 0

2 years ago

How do you write 9/100 as a decimal? 0.09 9.0 0.9

ANTONII [103]

The first one is correct

6 0

2 years ago

Read 2 more answers