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salantis [7]
3 years ago
12

If Cara spins a spinner two times, then what is the probability that she will land on A or B on her first spin and B, C, D, or E

on her second spin?
Mathematics
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

1/6

Step-by-step explanation:

1 over 6 letters

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What does x equal in this question
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5 0
2 years ago
Please help!! giving brainlest , please be serious. due in a few minutes thanks!
Margaret [11]

The answer is -7

The arrows both point toward the left side, and sine there are seven spaces the arrows are going through, you subtract 7 spaces and get -7

Hope that helps.

7 0
2 years ago
Read 2 more answers
1) Diego measured the number of cups of water in 15 bottles of various sizes. He
Ivan

Answer:

8\frac{3}{4} cups.

Step-by-step explanation:

From the line plot made by Diego which represents bottle sizes in cups, we can see that the most common size is the bottle having 1¾ cups (there are 5 of this sizes).

If he poured all 5 of this bottle sizes in 1 container, he would have the following:

1\frac{3}{4} * 5 = \frac{7}{4}*5 = \frac{35}{4}

= 8\frac{3}{4} cups.

6 0
2 years ago
I need help with Q9 c, I’ve done a and b if it helps, b=325 but I am just stuck on question 9C, I know the answer is 500N (as it
777dan777 [17]

Step-by-step explanation:

I know you've already done parts a and b, but I'll show the work for that before I do c.

Draw two free body diagrams, one for the car and one for the trailer.  The car pulls the trailer forward with a tension force T, so the trailer pulls backward on the car with an equal and opposite force T.

The car also has a 1200 N forward force from the engine, and a 200 N backwards force from resistance.

The trailer has a backwards resistance force of 100 N.

Sum of forces on the car:

∑F = ma

1200 − 200 − T = 900a

1000 − T = 900a

Sum of forces on the trailer:

∑F = ma

T − 100 = 300a

To solve the system of equations, first add the equations together.

1000 − 100 = 1200a

900 = 1200a

a = 0.75 m/s²

Plug back into either equation to find the tension force:

T = 325 N

Now for part c, draw new free body diagrams for the car and trailer.  This time, the car is pushing back on the trailer to slow it down.  So the trailer is pushing forward on the car with an equal and opposite force.  The magnitude of that tension force is given to be 100 N.

The car also has a backwards 200 N force from resistance, and a backwards brake force F.

The trailer has a backwards 100 N force from resistance.

Sum of forces on the car:

∑F = ma

100 − 200 − F = 900a

-100 − F = 900a

Sum of forces on the trailer:

∑F = ma

-100 − 100 = 300a

-200 = 300a

a = -⅔

Plugging into the first equation:

-100 − F = 900 (-⅔)

-100 − F = -600

F = 500 N

4 0
2 years ago
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