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Leto [7]
2 years ago
8

Liliana is renting a beach house for a family vacation. The house charges a $75 cleaning fee plus $95 per night. If Liliana want

s to spend a maximum of $645 on the rental, which inequality represents “n”, the number of nights can she afford to rent the beach house?
Mathematics
2 answers:
liubo4ka [24]2 years ago
7 0

Answer:

She can spend 6 nights in the beach house

Elenna [48]2 years ago
6 0
95n+75 is less than or equal to 645. 645-75=570. 95n is less than or equal to 570. 570/95=6. A maximum of six nights
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How does knowing some constructions help you do other, more complicated constructions
Nana76 [90]

Answer:

the first thing you learned is the base. then you can build off of it. just like math. you learn simple adding then you go onto multiplication and division.

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2 years ago
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Factor completely. y2+6y+8
zloy xaker [14]
If you can't see the picture the answer is: (y+4)(y+2).

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3 years ago
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Kesha threw her baton up in the air from the marching band platform during practice. The equation h(t) = −16t² + 54t + 40 gives
lapo4ka [179]

Answer:

a) 40 feet

b) 54 ft/min

c) 4 mins

Step-by-step explanation:

Solution:-

- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.

- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:

                           h ( t ) = −16t² + 54t + 40

Which gives the height of the baton from ground at time t mins.

- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.

- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:

                         h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40

                         h ( 0 ) = hi = 0 + 0 + 40 = 40 feet

Answer: The height of the platform hi is 40 feet.

- The speed ( v ) during the parabolic path of the baton also varies with time t.

- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.

                        v ( t ) = dh / dt

                        v ( t )= d ( −16t² + 54t + 40 ) / dt

                        v ( t )= -2*(16)*t + 54

                        v ( t )= -32t + 54

- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.

Hence,

                        v ( 0 ) = vi = -32*( 0 ) + 54

                        v ( 0 ) = vi = 54 ft / min

Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min

- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.

- The height of the ball at ground is zero. Hence,

                     h ( t ) = 0

                     0 = −16t² + 54t + 40

                     0 = -8t^2 + 27t + 20

- Use the quadratic formula to solve the quadratic equation:

                     

                    t = \frac{27+/-\sqrt{27^2 - 4*8*(-20)} }{2*8}\\\\t = \frac{27+/-\sqrt{1369} }{16}\\\\t = \frac{27+/-37 }{16}\\\\t =  \frac{27 + 37}{16} \\\\t = 4

Answer: The time taken for the baton to hit the ground is t = 4 mins

3 0
3 years ago
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GaryK [48]

Answer:

r = π C , C = 12 − x , t h e n r = π ( 12 − x ) = 12 π − π x

Step-by-step explanation:

So cutting the wire of 12 m in length into two pieces, x and 12-x. The x side will be made into the square so that the square has sides x/4 and an area of (x/4)^2. This means the length of the wire 12-x will be the circumference of the circle. So if: r = π C , C = 12 − x , t h e n r = π ( 12 − x ) = 12 π − π x i hope this is correct

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3 years ago
In the figure, ∠1 ≅ ∠2, ∠3 ≅ ∠4, and . You can justify the conclusion that ∠TKL ≅ ∠TLK by stating _____
VladimirAG [237]
From the question, we know that we will be looking at <3, <4, and angles TKL and TLK. That being said, since <3 is congruent to <4, that means that angles TKL and TLK, which are each supplementary to either angle 3 or 4, are congruent because, since angles 3 and 4 are congruent, they are congruent because the supplements of congruent angles are congruent. 
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2 years ago
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