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alex41 [277]
3 years ago
9

Can someone find the missing numbers???? Plz answer

Mathematics
1 answer:
Montano1993 [528]3 years ago
7 0
Iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii             dddddddddddddddoooooooooooooooonnnnnnnnnnnnnnn''''''''''''''ttttttttttttttttttttttttttttttttt                      kkkkkkkkkkkkkkkkkkkkkkkkkknnnnnnnnnnnnnnnnnnnnnnooooooooooooooowwwwwwwwwwwwwwwwwwwwwww
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I'll give points just please help(it's a little long sorry:( A student randomly selects some crayons from a large bag of crayons
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the probability of selecting a blue crayon for the bag is 16.7% while estimate probability of selecting a red crayon is 20% and the most likely crayon to be selected is brown crayon and also the possibility of getting a real possibility of the number of crayons in the bag is 60

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4 years ago
Solve the system of the linear equation by adding or subtracting.
Natali [406]
X=1 and y=-2  

In ordered pairs it would be (1,0) and (0,-2)
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HELP HELP HELP DUE IN 12 mins
Ghella [55]

Answer:

We can't seee the whole problem...

Step-by-step explanation:

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3 years ago
1+14554345555556675566669877
zhenek [66]
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3 years ago
Read 2 more answers
HELP i’m having trouble with my homework assignments
Aleksandr-060686 [28]

Answer:

Collin: about $401 thousand

Cameron: about $689 thousand

Step-by-step explanation:

A situation in which doubling time is constant is a situation that can be modeled by an exponential function. Here, you're given an exponential function, though you're not told what the variables mean. That function is ...

P(t)=P_0(2^{t/d})

In this context, P0 is the initial salary, t is years, and d is the doubling time in years. The function gives P(t), the salary after t years. In this problem, the value of t we're concerned with is the difference between age 22 and age 65, that is, 43 years.

In Collin's case, we have ...

P0 = 55,000, t = 43, d = 15

so his salary at retirement is ...

P(43) = $55,000(2^(43/15)) ≈ $401,157.89

In Cameron's case, we have ...

P0 = 35,000, t = 43, d = 10

so his salary at retirement is ...

P(43) = $35,000(2^(43/10)) ≈ $689,440.87

___

Sometimes we like to see these equations in a form with "e" as the base of the exponential. That form is ...

P(t)=P_{0}e^{kt}

If we compare this equation to the one above, we find the growth factors to be ...

2^(t/d) = e^(kt)

Factoring out the exponent of t, we find ...

(2^(1/d))^t = (e^k)^t

That is, ...

2^(1/d) = e^k . . . . . match the bases of the exponential terms

(1/d)ln(2) = k . . . . . take the natural log of both sides

So, in Collin's case, the equation for his salary growth is

k = ln(2)/15 ≈ 0.046210

P(t) = 55,000e^(0.046210t)

and in Cameron's case, ...

k = ln(2)/10 ≈ 0.069315

P(t) = 35,000e^(0.069315t)

5 0
3 years ago
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