The average speed, in km/minute, of the train is 2.79 km/minute
<h3>Calculating average speed </h3>
From the question, we are to calculate the average speed in km/minute
From the given information,
Distance travelled = 503 km
Time taken = 3 hours = 3 × 60 minutes = 180 minutes
Using the average speed formula,
Average speed = Distance / Time
∴ Average speed of the train = 503 / 180
Average speed of the train = 2.79 km/minute
Hence, the average speed, in km/minute, of the train is 2.79 km/minute
Learn more on Calculating average speed here: brainly.com/question/12025128
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To find it, evaluate it at the endpoints and the vertex
in form
f(x)=ax²+bx+c
the x value of the vertex is -b/2a
given
c(t)=1t²-10t+76
x value of vertex is -(-10)/1=10
evaluate c(0) and c(13) and c(10)
c(0)=76
c(13)=115
c(10)=76
it reached minimum in 2000 and 2010
porbably teacher wants 2010
the min value is $76
Answer:
<h2>800%</h2>
Step-by-step explanation:
Let p represent the population
in 1965 → the population becomes 2p
in 1970 → the population becomes 2(2p) = 4p
in 1975 → the population becomes 2(4p) = 8p
p ——————> 100%
8p ————-—-> x%
then
I think you should do this equation
So there is an identity we'll need to use to solve this:
cos(x+y) = cosxcosy - sinxsiny
replace the numerator with the right hand side of that identity and we get:
(cosxcosy - sinxsiny)/cosxsiny
Separate the numerator into 2 fractions and we get:
cosxcosycosxsiny- sinxsiny/cosxsiny
the cosx's cancel on the left fraction, the siny's cancel on the right fraction and we're left with:
cosy/siny - sinx/cosx
which simplifies to:
coty - tanx
