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2 years ago

Calculate the area of a circle with a radius of 8 feet

Mathematics

1 answer:

Ulleksa [173]2 years ago

3 0

Answer:

201.06 square feet

Step-by-step explanation:

area of a circle is given by πr², where π = 3.1416

A = 3.1416 * 8²

A = 3.1416 * 64 = 201.0624 square feet

A = 201.06 square feet

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How can you tell when a pattern shows counting by tens ?

mestny [16]

They end in 0? i think

4 0

3 years ago

Read 2 more answers

6x-14<-14 or 3x+10>13

kow [346]

Step-by-step explanation:

not sure the question but I can solve the equations

6x-14<-14

6x<0

×<0

3x+10>13

3x>3

×>1

7 0

2 years ago

A changes saved<br> Set up a proportion and use it to solve for x.<br> 2<br> 10<br> х<br> 3

V125BC [204]

Answer:

C. 15

Step-by-step explanation:

The following proportional can be set-up for the figure given:

$\frac{x + 3}{x} = \frac{10 + 2}{10}$

Solve for x

$\frac{x + 3}{x} = \frac{12}{10}$

$\frac{x + 3}{x} = \frac{6}{5}$

Cross multiply

$5(x + 3) = x(6)$

$5x + 15 = 6x$

15 = 6x - 5x

15 = x

x = 15

3 0

2 years ago

Find the exact value of cos theta, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.

vova2212 [387]

Answer:

$cos \theta = -\frac{8}{17}$

Step-by-step explanation:

For this case we know that:

$sin \theta = \frac{15}{17}$

And we want to find the value for $cos \theta$ , so then we can use the following basic identity:

$cos^2 \theta + sin^2 \theta =1$

And if we solve for $cos \theta$ we got:

$cos^2 \theta = 1- sin^2 \theta$

$cos \theta =\pm \sqrt{1-sin^2 \theta}$

And if we replace the value given we got:

$cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}$

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

$cos \theta = -\frac{8}{17}$

5 0

2 years ago

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Pavel [41]

$\boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}$

<h2>Explanation:</h2>

Using the quadratic formula:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}$

<h2>Learn more:</h2>

Quadratic functions: brainly.com/question/12164750

#LearnWithBrainly

8 0

2 years ago