Answer:
a) X( w ) = 1 /jw - e^-jw / jw
b) X1(t) = 1 for 0.5
X1(t) = 0 for elsewhere
Step-by-step explanation:
x(t) continuous time function = 1
interval ( 0,1 ) also x(t) = 0 outside the given interval
a) Determine the continuous time Fourier transformation of x(t)
x( t ) = u(t) - u(t - 1 )
x ( w ) = 1 /jw - e^-jw / jw
b) supposing x1(t) = x(2t)
x1(t) = u(t) - u ( t - 0.5 )
x1(t) = 1 for 0.5
x1(t) = 0 for elsewhere
1/3 = 4/12
5/12 = 5/12
1/6 = 2/12
4/12 + 5/12 + 2/12 = 11/12
12/12 - 11/12 = 1/12
1/2 of milk is left over.
100
Why:
125-25 is 100
25-25 is 0 so it’ll give you 100
09.76 laos jajskwiqisnbsbsbsbsb
<span>f(x)=2x+5
then
</span><span>f(4)=2(4) +5 = 8 + 5 = 13
hope it helps</span>
