How can you solve this system of equations using substitution?
-66x-2z=-196
8x+2z=22
1 answer:
In the second equation:
Subtract 8x from both sides.
2z = 22 - 8x
Divide 2 on both sides.
z = 11 - 4x
Plug this into the first equation.
-66 - 2(11 - 4x) = -196
-66 - 22 + 8x = -196
Combine like terms.
-88 + 8x = -196
Add 88 to both sides.
8x = -108
Divide 8 on both sides.
x = -13.5
Put this into the second equation.
8(-13.5) + 2z = 22
-108 + 2z = 22
Add 108 to both sides.
2z = 130
Divide 2 on both sides.
z = 65
and
x = -13.5
Hope this helps!
You might be interested in
It's a combination:
I=k/d^2
4=k/d^2 and 1=k/64 so if we divide the first by the second we get:
4/1=(k/d^2)/(k/64)
4=(k/d^2)*(64/k)
4=64/d^2
d^2=64/4
d^2=16
d=4 meters
24 : 12.5/100 = 24 * 100/12.5 = 192;
Answer:
its 55
Step-by-step explanation: