∫ e^(3x)*(cosh(2x)dx
= ∫ [e^(3x)*(e^(2x)+e^(-2x))/2]dx
= ∫ [(e^(5x)+e^x)/2]dx
=e^(5x)/10+e^x/2+C
=(1/10)(e^(5x)+5e^x)+C
Answer:
17/60
Step-by-step explanation:
Answer:
T = 24 so it would be 24x24=576 square units
Step-by-step explanation:
How did we calculate this triangle?
The calculation of the triangle progress in two phases. The first phase is such that we try to calculate all three sides of the triangle from the input parameters. The first phase is different for the different triangles query entered. The second phase is the calculation of other characteristics of the triangle, such as angles, area, perimeter, heights, the center of gravity, circle radii, etc. Some input data also results in two to three correct triangle solutions (e.g., if the specified triangle area and two sides - typically resulting in both acute and obtuse) triangle).
Answer:
Hello There!
Your answer is 1/56
Step-by-step explanation:
1/7 (1/8)
You can literally just take out 7 and 8 and multiply than put it back to the proper denominator.
Hope this helps!!
a.
20/2 = 10
0, 10, 20, 30, 40, 50
b.
32.4/4 = 8.1
0, 8.1, 16.2, 24.3, 32.4, 40.5
c.
8.8/4 = 2.2
0, 2.2, 4.4, 6.6, 8.8, 11
d.
10/3 = 3.3
0, 3.3, 6.7, 10, 13.3, 16.7
