Answer:The expression can be simplified in following steps;
Step-by-step explanation:
(16+a)+15=0
16+15+a=0
31+a=0
a=-31
<span>Your bowl contains 8 red balls, and 9 blue balls, and you draw 4 balls. in how many ways can the selection be made so that at least one of each color is drawn.</span>
First, you divide 17/9
You will get 1, your remainder as 8.
Using your denominator, your answer will be 1 8/9
3x^2(-5x^2-2x^2)
-15x^4-6x^4
-21x^4
I believe this is right. Not too sure. But I hope it helped a bit.
