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Igoryamba
3 years ago
13

3/5 divided by 2/3 please give me right answer hope

Mathematics
2 answers:
Ilya [14]3 years ago
8 0
.9 is the correct answer what you have to do Is take 3/5 and turn it into a decimal which is .6 and then do the same with 2/3 which is .66 repeating reduce down to .66 and divide you will get .9090909090909
antiseptic1488 [7]3 years ago
4 0
The answer for this would be 0.06.
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If , what is the truncation error for S4?
serious [3.7K]
It is 0.037 so that mean you are right but no right
7 0
3 years ago
Read 2 more answers
HELP
Ulleksa [173]

Answer:

Ok, to find MAD, you have to add up all of the decimals in the set, and then divide by how much decimals there are in the set.

Adding them all up...

The final result of the adding is 56.7

Now, we have to divide by how much decimals.

We now have. 56.7 / 6

Do the division.

56.7 / 6 ===> 9.45

No need to round, the final answer is 9.4

3 0
3 years ago
Find the slope of the line that passes through (3, 8) and (8, 5).
tino4ka555 [31]

Answer:

-⅗

Step-by-step explanation:

(5-8)/(8-3) = -3/5

8 0
3 years ago
Please help asap !!! giving out the brainliest answer
kotykmax [81]

Answer:

if you have to add it is 17  

if you have to divide it is 1.5  

if you have to subtract it is 16

Step-by-step explanation:

4 0
3 years ago
The 11th term of an progression is 25 and the sum of the first 4 terms is 49. The nth term of the progression is 49
KIM [24]

<u>Answer:</u>

<u>For 1:</u> The first term is 10 and the common difference is \frac{3}{2}

<u>For 2:</u> The value of n is 27

<u>Step-by-step explanation:</u>

The n-th term of the progression is given as:

a_n=a_1+(n-1)d

where,

a_1 is the first term, n is the number of terms and d is the common difference

The sum of n-th terms of the progression is given as:

S_n=\frac{n}{2}[2a_1+(n-1)d]

where,

S_n is the sum of nth terms

  • <u>For (1):</u>

The 11th term of the progression:

25=a_1+10d               .......(1)

Sum of first 4 numbers:

49=\frac{4}{2}[2a_1+3d              ......(2)

Forming equations:

98=8a_1+12d

25=a_1+10d                  ( × 8)

The equations become:

98=8a_1+12d

200=8a_1+80d

Solving above equations, we get:

102=68d\\\\d=\frac{102}{68}=\frac{3}{2}

Putting value in equation (1):

25=a_1+10\frac{3}{2}\\\\a_1=[25-15]=10

Hence, the first term is 10 and the common difference is \frac{3}{2}

  • <u>For 2:</u>

The nth term is given as:

49=10+(n-1)\frac{3}{2}

Solving the above equation:

39=(n-1)\frac{3}{2}\\\\n-1=26\\\\n=27

Hence, the value of n is 27

3 0
3 years ago
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