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3 years ago

Graph y=-2(x+1)^2+4 (must show all work that leads to your graph) please help

Mathematics

1 answer:

bogdanovich [222]3 years ago

3 0

Answer:

See explanation

Step-by-step explanation:

This is a parabola that opens down with the vertex at (-1, 4) So, find (-1, 4) on your graph. Now, find y for x = 0 and x = 1 which will give you two points on the parabola. Since the parabola is symmetrical, find the points that are the partners to the two points you just found. That should give you a good idea as the graph.

when x = 0,

y = -2(0 + 1)^2 + 4 = -2(1) + 4 = 2 so (0, 2) is on the graph

when x = 1,

y = -2(1 + 1)^2 + 4 = -2(2)^2 + 4 = - 8 + 4 = -4 so (1, -4) is on the graph

Symmetry gives the point (-2, 2) as the partner to (0, 2) and

(-3, -4) as the partner to (1, -4)

I don't have graph paper to show you that, you are going to have to graph those 5 points ((-1, 4), (0, 2), (1, -4), (-2, 2), (-3, -4)) and draw the parbola.

I hope this helps. OK?

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