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erastova [34]
3 years ago
15

$4.50 per 1 Kilogram How many kilograms can you buy with $10

Mathematics
1 answer:
Dafna1 [17]3 years ago
8 0

Answer:

2.23kg

Step-by-step explanation:

If you can get 1 kg for $4.50. You can perform a ratio to find out how much you get for $10.

1/4.50=x/10

.2222222=x/10

multiply the 10 on both sides

x=2.23 kg for $10

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The dollar-mart grocery stores sales six bars of soap for $1. how many soaps can a customer buy with $9.
jeka94

Answer:

54

Step-by-step explanation:

6 bars of soap = $1

x bars of soap = $9

We need to multiply both sides of the equation by the same amount so that $9 is on the right.

$1 x 9 = $9

6 x 9 = 54

So, you can buy 54 soaps with $9.

Hope this makes sense. Feel free to ask further if need be.

8 0
2 years ago
Given the information for Whelan Inc, in problem 10 and 11, suppose you also know that the firm's net capital spending for 2019
kotykmax [81]

Answer:

Based on information provided the only line item that falls in the Operating Cash Flow is Reduction in Net Working Cash Flow. Capital Spend comes under Investing Cash Flow. Debt, Interest payment, Dividend payment and capital surplus come under Financing Cash flow.

A reduction in net cash flow increases the cash flow for the company. Thus the OCF equals +$94,300 for the company.

Step-by-step explanation:

8 0
3 years ago
A sphere and a cylinder have the same radius and height. The volume of the cylinder is 21m. what is the volume of the sphere.​
Goshia [24]

Answer:

The volume of the sphere is 14m³

Step-by-step explanation:

Given

Volume of the cylinder = 21m^3

Required

Volume of the sphere

Given that the volume of the cylinder is 21, the first step is to solve for the radius of the cylinder;

<em>Using the volume formula of a cylinder</em>

The formula goes thus

V = \pi r^2h

Substitute 21 for V; this gives

21 = \pi r^2h

Divide both sides by h

\frac{21}{h} = \frac{\pi r^2h}{h}

\frac{21}{h} = \pi r^2

The next step is to solve for the volume of the sphere using the following formula;

V = \frac{4}{3}\pi r^3

Divide both sides by r

\frac{V}{r} = \frac{4}{3r}\pi r^3

Expand Expression

\frac{V}{r} = \frac{4}{3}\pi r^2

Substitute \frac{21}{h} = \pi r^2

\frac{V}{r} = \frac{4}{3} * \frac{21}{h}

\frac{V}{r} = \frac{84}{3h}

\frac{V}{r} = \frac{28}{h}

Multiply both sided by r

r * \frac{V}{r} = \frac{28}{h} * r

V = \frac{28r}{h} ------ equation 1

From the question, we were given that the height of the cylinder and the sphere have equal value;

This implies that the height of the cylinder equals the diameter of the sphere. In other words

h = D , where D represents diameter of the sphere

Recall that D = 2r

So, h = D = 2r

h = 2r

Substitute 2r for h in equation 1

V = \frac{28r}{2r}

V = \frac{28}{2}

V = 14

Hence, the volume of the sphere is 14m³

4 0
3 years ago
Read 2 more answers
Find the product.
IrinaK [193]
(2n+1)(2n-1)(n+5)
=(4n^2+2n-2n-1)(n+5)
=(4n^2-1)(n+5)
=4n^3-n+20n^2-5
4n^3+20n^2-n-5
4 0
3 years ago
Which statement describes the system of equations
Contact [7]

Answer:

2y-2x-2y= - 22x = 0x + 2y  = 1

Step-by-step explanation:

7 0
3 years ago
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