A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 640t
1 answer:
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Answer:
<h3>b) 850.1 centimeters.</h3>Step-by-step explanation:
To find the area of this figure, we must first find the areas of the shapes that compose this figure.
This figure is made up of a rectangle and a semicircle.
Remember: To find the area of a semicircle, multiply the radius by itself twice, then multiply the product pi, lastly divide the product by 2.
<u>3.14 will be used for pi!</u>
To find the area of a rectangle, multiply the length by the width. The product is the area of the rectangle.
Now, let's solve.
The diameter of the semicircle is 32 centimeters.
To find the radius of a semicircle, divide the diameter by 2.
The radius of the semicircle is 16 centimeters.
Now that we have the radius, we can find the area of the semicircle.
The area of the semicircle is 401.92 centimeters.
Furthermore, we find the area of the rectangle.
The area of the circle is 448 centimeters.
Next, we add the areas of both shapes to find the area of this figure.
The final step is to round 849.92 to the nearest tenth.
Even though 849.92 to rounded to the nearest tenth is 849.9, there is no answer choice for this. The closest one to this answer is choice 'b.'
I, therefore, believe the area of this figure is 850.1 centimeters.
Answer:
- zeros: x = -3, -1, +2.
- end behavior: as x approaches -∞, f(x) approaches -∞.
Step-by-step explanation:
I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.
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The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...
x² +x -6
which factors as (x -2)(x +3), so telling you the remaining roots are -3 and +2.
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For any odd-degree polynomial with a positive leading coefficient, the sign of the function will match the sign of x when the magnitude of x gets large. Thus as x approaches negative infinity, so does f(x).
