Answer:
36.0555
Step-by-step explanation:
Answer:
After 4s
Step-by-step explanation:
Given the ball is initially projected upwards with a velocity of 64ft per sec and we are required to find the time at which it reaches the ground .There are many approaches to solve this problem we will follow this one:
It is also known as the time of flight for the ball which can be found by doubling the time taken for the ball to reach to its maximum height or the point where velocity is zero.
Now 
For the time taken to reach the max height
.
Which implies that -32t+v=0.
∴Time taken to travel halfway through the path =2sec.
∴total time =
Remark
You are dealing with a right angle triangle. You can use one of Sin(x) Cos(x) or Tan(x). Since the Hypotenuse is involved and since you are given the adjacent side, Cos(71) is what you will need.
Solution
H = BC
Cos(x) = adjactent / hypotenuse
Cos(71) = 6.3 / H Multiply both sides by H
H * Cos(71) = 6.3 Divide by Cos(71)
H = 6.3 / cos(71) Cos(71) = 0.32557
H = 6.3 / 0.32557 Divide
H = BC = 19.351 Answer
The first one is correct (-2/3, -1/2, 7/12, 0.82) pls mark branliest
I hope this answer helps, it’s kinda messy, but it’s still understandable (I guess)