Johann wants to find a rectangular solar panel with an area of 128 cm. If the

Mathematics

1 answer:

Papessa [141]3 years ago

8 0

Answer:

The length of rectangular panel is 6.4 cm.

Step-by-step explanation:

We are given the following information in the question:

Area of rectangular solar panel = 128 square cm

Width of panel = 20 cm

We have to find the length of the panel

Formula:

$\text{Area of rectangular panel} = \text{Width}\times \text{Length}\\\Rightarrow 128 = 20\times \text{Length}\\\\\text{Length} = \displaystyle\frac{128}{20} = 6.4\text{ cm}$

Hence, the length of rectangular panel is 6.4 cm.

This is an example of direct variation as greater would be length and breadth, the greater would be the area.

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Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

On the other hand, $\delta \leq x+\epsilon-y$ then $z$ hence $z$ . Combining the inequalities, we have that $x-\epsilon$ , therefore $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ as required.