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IrinaVladis [17]
3 years ago
15

Milo's pancake recipe makes 9 servings. It calls for 3/4 cup milk. Milo wants to make 6 servings. How much milk will he need?

Mathematics
2 answers:
MrRa [10]3 years ago
7 0

It says that the recipe for 9 servings would require 3/4 cup milk.

He wants to prepare recipe for 6 servings. Let's assume it requires X cups milk.

Now we can use concept of proportions to solve this problem.

The proportion of X cups for 6 servings would be same as 3/4 cup milk for 9 servings. Mathematically, we can write it as follows :-

\frac{X \;cups \;milk}{6 \;servings} = \frac{\frac{3}{4} \;cups \;milk}{9 \;servings} \\\\ Or\; \frac{X \;cups \;milk}{\frac{3}{4} \;cups \;milk} = \frac{6 \;servings}{9 \;servings} \\\\ \frac{X }{\frac{3}{4} } = \frac{6 }{9 } \\\\ X = \frac{6}{9}*\frac{3}{4}  \\\\ X = \frac{6*3}{9*4} \\\\ X = \frac{18}{36} \\\\ X = \frac{1}{2} \;cup \;milk

Hence, we require \frac{1}{2} cup milk for 6 servings.

Reil [10]3 years ago
5 0
1/2 cup of milk for 6 servings
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What is the percent of change from 60 to 87?
stiv31 [10]

Answer:

45% increase

Step-by-step explanation:

The new number (87) is bigger than the original number (60), so this is a percent increase.

To find the percent of change, which in this case is a percent increase, take the change amount and divide by the original, then convert to a percent.

Subtract to find the change.

87 - 60 is 27.

27 is the amount of change.

change/original

= 27/60

= .45

Times by 100 to change to a percent.

.45 × 100

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2 years ago
Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result
Vaselesa [24]

<u>Complete Question:</u>

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

<u>Correct Answer:</u>

A) (10-x)(12-x)=15

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

<u>Step-by-step explanation:</u>

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

length=10-x\\breadth=12-x

According to question , Area of new image is :

⇒ Area = \frac{1}{8}Length(breadth)

⇒ Area = \frac{1}{8}(10)(12)

⇒ Area = 15

So the equation will be :

⇒ (10-x)(12-x)=15

b. Find the dimensions of the reduced image

Let's solve :  (10-x)(12-x)=15

⇒ 120-10x-12x+x^2=15

⇒ 120-22x+x^2=15

⇒ x^2-22x+105=0

By Quadratic formula :

⇒ x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x = \frac{22 \pm8 }{2}

⇒ x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}

⇒ x = 15 , x =7

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ x =7

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

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