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Andreyy89
3 years ago
7

1. y= 2x - 3 y=-3x + 2

Mathematics
1 answer:
Bond [772]3 years ago
8 0

Answer:

x=1,y=-1

Step-by-step explanation:

the ans is 1 and -1.

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PLEASE HELP I WILL LITERALLY CASHAPP YOU IF YOU CAN ANSWER THIS CORRECTLY THIS IS NOT A JOKE
weqwewe [10]

Answer:

f(x) = 5x - 30

Yes it is a function

Step-by-step explanation:

Because when you input 0 you get -30 we know it starts at 0 or (0,-30). This gives us b in the equation y = mx + b.

We know that for every 4 cars washed it increases by 20. So 20/4 is 5. This tells us m = 5.

Plug it all in and you get  y = 5x - 30 or f(x) = 5x - 30

8 0
3 years ago
What is the area of this composite figure?
12345 [234]

Answer:

216

Step-by-step explanation:

the area is ((B + b) x h) / 2

which is ((22 + 14) x 12) / 2

4 0
3 years ago
Read 2 more answers
In statistics, the middle value of an ordered set of values is called what?
Bond [772]
It is called the median :)
8 0
3 years ago
Pls can you solve this question from hegartymaths?
Sergeeva-Olga [200]

The area of a circle with radius r is πr². So you need to find r such that

πr² = 56π

⇒   r² = 56

⇒   r = √56 = 2√14

8 0
3 years ago
The frequency, f, in Hz, at which a simple pendulum rocks back and forth is given by 1 , 2 g f π l = where g is the strength of
Monica [59]

Answer:

a. 0.9 Hz b. 0.37 Hz

Step-by-step explanation:

The frequency of the simple pendulum f = (1/2π)√g/l where g = acceleration due to gravity and l = length of pendulum

a. Find the frequency of a pendulum whose length is 1 foot and where the gravitational field is approximately 32 ft/s2

To find f on Earth, g = 32 ft/s² and l = 1 ft

So, f =  (1/2π)√(g/l)

f = (1/2π)√(32 ft/s²/1 ft)

f = (1/2π)√(32/s²)

f = (1/2π)(5.66 Hz)

f = 0.9 Hz

b. The strength of the gravitational field on the moon is about 1/6 as strong as on Earth.. Find the frequency of the same pendulum on the moon.

On the moon when acceleration due to gravity g' = g/6,

f =  (1/2π)√(g'/l)

f =  (1/2π)√(g/6l)

f = (1/2π)√[32 ft/s²/(6 × 1 ft)]

f = (1/2π)√(32/s²)/√6

f = (1/2π)(5.66 Hz)/√6

f = 0.9/√6 Hz

f = 0.37 Hz

3 0
3 years ago
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