You would of taken 28 dollars away after 7 days because if your taking away 4$ each day you just have to figure out 4 times what equals 28 witch is 7
So the answer is 7 days
Answer:
Answer is 0.5
Step-by-step explanation:
The text implies that the number of traffic accidents determines the number of ambulances required on the road. Hence, 1 traffic accident requires 1 ambulance.
The time slot and time of day remain same in both the text and the question.
The average or mean number of accidents is 1.1
QUESTION: What then is the probability that there is need for exactly 2 ambulances on that road and in that time frame?
In other words, what is the probability that there'll be 2 accidents on that road and in that time frame?
Since the mean number of accidents is 1.1, 2 is above the mean.
Probability of 1.1 accidents is 1, since that's the mean (expected value).
Probability of 2 accidents is 1/2 which is = 0.5
Answer:
9
Step-by-step explanation:
By joining N to L, you will have a right angled triangle which is right angle at N. Then r^2+36=(3+x)^2. r=9/2. PQ=2r=9
Answer:
<em>Choose the first alternative</em>

Step-by-step explanation:
<u>Probabilities</u>
The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions
and the total number of possible choices
, i.e.

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total
We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.
To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

The total number of possible choices is

The probability is then

Choose the first alternative