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Art [367]
2 years ago
13

Fill in the blank using a term found in the vocabulary list. The ratio of the value of a subtotal to the value of the total is c

alled _________________.
Mathematics
1 answer:
lina2011 [118]2 years ago
5 0

Answer:

Relative frequency

Step-by-step explanation:

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Select all equations that can represent the question: "How many groups of 45 are in 1?" A ?⋅1=45? Times 1 is equal to 4 fifths B
Aleonysh [2.5K]

This question is not correctly written.

Complete Question

Select all equations that can represent the question: "How many groups of 4/5 are in 1?" A ?⋅1=4/5? Times 1 is equal to 4 fifths B 1⋅4/5=?1 times 4 fifths is equal to ? C 4/5÷1=?4 fifths divided by 1 is equal to ? D ?⋅4/5=1? Times 4 fifths is equal to 1 E 1÷4/5=?1 divided by 4 fifths is equal to ?

Answer:

D ?⋅4/5=1 = ? Times 4 fifths is equal to

E 1÷4/5=? = 1 divided by 4 fifths is equal to

Step-by-step explanation:

How many groups of 4/5 are in 1?

The operation used to solve this is that Division operation.

Hence, we solve it by saying:

1 ÷ 4/5 = ?

= 1× 5/4 = ?

5/4 = ?

Cross Multiply

5 = 4 × ?

? = 5/4

The equations that can represent the question: is

Option D ?⋅4/5=1 = ? Times 4 fifths is equal to

Option E 1÷4/5=? = 1 divided by 4 fifths is equal to

7 0
2 years ago
Someone answer and explain PLEASE ILL MARK BRAINLIEST
JulsSmile [24]

Answer:

i beleive 9 times

Step-by-step explanation:

50÷5.50=9.09

3 0
2 years ago
PLEASE HELP!!! WHOEVER GETS THE ANSWER RIGHT GETS BRAINLIEST!!!
masha68 [24]

There is 4 X so you use 360- (11+1) which is 348 and now divide by 4 which is now 87

<h2>Thank you for asking</h2><h2 /><h2>From Cambridge</h2><h2 />
7 0
2 years ago
Read 2 more answers
g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20
Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

X\sim N(\mu = 50, \sigma =6)

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0
3 years ago
121degree 22' 36'' is like same as what?
Darina [25.2K]
22' is 22 minutes
there are 60 minutes in 1 degree, how many in 22? well, the short answer is you divide it by 60, or 22/60 0.37 or thereabouts, so that makes it 

121.037 degrees and 36''

36'' is 36 seconds, there are 60 seconds in 1 minute, so in short, just divide it by 60 as well, so 36/60 or 0.6 minutes

so, let us revise above some

121 degrees 22' and 36''

22' and 36'' is 22.6'  because 36'' is 0.6'

how much is 22.6' in degrees?  well 22.6/60
or about .38

so. 121° 22' 36'' will  be 121.38° approximately
5 0
3 years ago
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