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Zinaida [17]
3 years ago
13

-1x + 5 = 10 solution please

Mathematics
2 answers:
emmainna [20.7K]3 years ago
5 0

Answer: x=-5

<u>Simplify both sides of the equation</u>

<u></u>-x+5=10<u></u>

<u></u>

<u>Subtract 5 from both sides</u>

<u></u>-x+5-5=10-5\\-x=5<u></u>

<u></u>

<u>Divide both sides by -1</u>

<u></u>x/-1=5/-1\\x=-5<u></u>

FinnZ [79.3K]3 years ago
3 0

Answer:i think its -5 because if you subtract 5 from 10 then its five hnd a negative times a negative is a positive

Step-by-step explanation:

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Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



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