Answer:
14
Step-by-step explanation:
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
-5^11 you want to subtract -6 from 5 which become 5+6.
When we solve the equation, we will get the real answer <u>x=40</u> as a variable.
<h3>First Degree Equation</h3>
First degree equation is a mathematical sentence, which has values represented by letters.
These letters can indicate a variable or an unknown - which at the end of the equation will be the final value.
— To solve this equation, just: apply the distributive property (multiply the terms that are outside the parentheses, for the terms that are inside the symbol).
— Next, let's add the real numbers together. Next, we'll subtract the like terms before the equality, thus moving the common term after the equality by adding.
— Finally, let's divide the equation, thus obtaining the final result.
4 + 3(x + 22) = 5x - 10
4 + 3x + 66 = 5x - 10
70 + 3x = 5x - 10
3x - 5x = -10 - 70
-2x = -80
x = 80 ÷ 2
<u>x = 40</u>
Therefore, the correct value of X in this equation, will be <u>x = 40</u>.
Answer:
Step-by-step explanation:
3 - 13x - 7x^2 - (5x^2 + 12x - 10) =
3 - 13x - 7x^2 - 5x^2 - 12x + 10 =
- 12x^2 - 25x + 13 <===
