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zhenek [66]
3 years ago
15

Find the surface area of the triangular prism shown ​

Mathematics
1 answer:
patriot [66]3 years ago
4 0

The surface area of the triangular prism is 144 cm²

<u>Explanation:</u>

Given:

Base of the triangle = 4

Height of the triangle = 3

Hypotenuse of the triangle = 5

Length of the prism = 11

Surface area of the rectangular prism = ?

Surface area, A = ah + bh + ch + \frac{1}{2} \sqrt{-a^4+2(ab)^2 + 2(ac)^2-b^4 + 2(bc)^2 - c^4}

On substituting the value, we get:

A = 4 X 11 + 3 X 11 + 5 X 11+\frac{1}{2} \sqrt{-(4)^4 + 2(4X3)^2+2(4X5)^2-3^4 + 2(3X5)^2 - 5^4} \\\\A = 144 cm^2

Therefore, the surface area of the triangular prism is 144 cm²

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We have that:

\frac{45}{40} = \frac{9}{8}

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Neporo4naja [7]

Answer:

The two consecutive odd integers are -17 , -15 <em>OR</em> 15 , 17

Step-by-step explanation:

* Lets explain how to solve the problem

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 is x + 2

∴ The two consecutive odd integers are x and x + 2

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∵ The square of x is x²

∵ the square of x + 2 is (x + 2)²

∵ the sum of their squares is 514

∴ x² + (x + 2)² = 514

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∵ x² + (x + 2)² = 514

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∵ (x + 2)² = (x)(x) + 2(x)(2) + (2)(2)

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∴ 2x² + 4x + 4 = 514

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∴ 2x² + 4x - 510 = 0

- All the terms have 2 common factor, then divide both sides by 2

∴ x² + 2x - 255 = 0

- Factorize the quadratic into two factors

∴ (x + 17)(x - 15) = 0

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