24- 1,2,3,4,6,8,12,24
64-1,2,4,8,16,32,64
88-1,2,4,8,11,22,44,88
Here are all the factors.^^
The common factors are 1,2,3,4,6
Hope this helps!
Answer:
Step-by-step explanation:
given that a deck of cards is shuffled.
we know in a deck there are 52 cards, 13 cards of each variety spade, clubs hearts and dice. Red are 26 and black are 26. kings, will be 4.
(a) the top card is the king of spades and the bottom card is the queen of spades?
(iii) 1/52 × 1/52
Top has 1/52 and bottom has 1/52 and these are independent.
(b) the top card is the king of spades and the bottom card is the king of spades?
(viii) None of the above
Because it is impossible.
(c) the top card is the king of spades or the bottom card is the king of spades?
(iv) 1/52 + 1/52
This is the sum of probabilities because there is no common event for these two.
(d) the top card is the king of spades or the bottom card is the queen of spades?
(ii) 1/52 + 1/51 (once king of spades is there, then probability is 1/51 for bottom card)
(e) of the top and bottom cards, one is the king of spades and the other is the queen of spades?
(vii) 2/52 × 1/51
Because this is twice of probability d.
The answer to "Round 10.054 To 2 decimal places" is 10.05
The answer is 275. hope it helps :)
Answer:
E is not a subspace of 
Step-by-step explanation:
E is not a subspace of
In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.
Consider
(a,b) = (1,1)
(c,d) = (-1,-1)
It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.
But (a,b) + (c,d) = (1-1, 1-1) = (0,0)
and (0,0) is not in E.
By the way, it can be proved that in any vector space all sub spaces must have the vector zero.
