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Studentka2010 [4]

3 years ago

10

The complete set of common factors of 6 and 12 is:

1 answer:

trapecia [35]3 years ago

3 0

The complete set of common factors of 6 and 12 is D. {1,2,3,6}

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Geometry is experienced that in the early childhood setting through

vampirchik [111]

playing with blocks??

7 0

3 years ago

An ice-skating competition lasted three days. Day one had an attendance of 16,390 people. Day two had an attendance of 16,550 pe

lana [24]

Answer:

$Day\ 3 = 16237$

$Day\ 1 = 16390$

$Day\ 2 = 16550$

Step-by-step explanation:

Given

$Day\ 1 = 16390$

$Day\ 2 = 16550$

$Day\ 3 = 16237$

Required

Order from least to greatest

Comparing 16390, 16550 and 16237.

The order of arrangement from least to greatest is:

16327, 16390 and 16550.

So, we have:

$Day\ 3 = 16237$

$Day\ 1 = 16390$

$Day\ 2 = 16550$

6 0

3 years ago

1. A new brand of hot dog claims to have a lower sodium content than the leading brand.

kherson [118]

Answer:

(a) Population mean = 314.5mg

(b) Margin of error = 21.281mg

(c) No, 350mg is not a plausible value

The new brand of hot dog has a lower sodium content on average than the leading brand

(d) Yes

Step-by-step explanation:

(a) Population mean = (370+326+322+297+326+289+293+264+327+331)/10 = 3145/10 = 314.5mg

(b) Margin of error = t×sd/√n

sd = 29.73, n = 10, degree of freedom = n-1 = 10-1 = 9

Assuming 95% confidence level

t-value corresponding to 9 degrees of freedom and 95% confidence level is 2.262

Margin of error = 2.262×29.73/√10 = 21.281mg

(c) No

Lower limit of new brand = 314.5 - 21.281 = 293.219mg

Upper limit = 314.5 + 21.281 = 335.781mg

The range of sodium content for the new brand of hot dog is between 293.219mg and 335.781mg which is lower than the leading brand (350mg)

(d) Margin of error = t×sd/√n

From the formula above, margin of error varies inversely as the square root of sample size

The smaller the sample size (n = 10) the larger the margin of error and the less accurate is the population mean

The larger the sample size (n = 40) the smaller the margin of error and the more accurate is the population mean

8 0

3 years ago

Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

(c) $4(m+n)=4m+4n$ (using $a(b+c)=ab+ac$ )

(d) $3(5-q)=15-3q$ (using $a(b-c)=ab-ac$ )

(e) $5(2c+1)=10c+5$ (using $a(b+c)=ab+ac$ )

(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

(i) $2(6a-4b+3)=2((6a-4b)+3)$

⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

(j) $6(m+n+p)=6((m+n)+p)$

⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

(m) $n(4-n)=4n-n^2$ (using $a(b-c)=ab-ac$ )

(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

(p) $2x(x+5)=2x^2+10x$ (using $a(b+c)=ab+ac$ )

(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

(s) $4a(3b+2c)=12ab+8ac$ (using $a(b+c)=ab+ac$ )

(t) $5p(4p-5q)=20p^2-25pq$ (using $a(b-c)=ab-ac$ )

6 0

3 years ago

The cost to join a yoga studio is $125, plus there is an additional $90 per month fee. If Kennedy has spent

Yuki888 [10]

215 +257 =15
Hope that work

4 0

3 years ago

Read 2 more answers