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defon
3 years ago
15

Data was collected on the average winter temperature and the number of days with

Mathematics
1 answer:
laila [671]3 years ago
6 0

Answer:

You should expect to see more days with snow when the average temperature is lower, and less days wth snow when the average winter temperature is higher.

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There were 75 roasted turkeys at Ally's Eats. Bob's Goods had 4/5 as many roasted turkeys as Ally's Eats. If Ally's Eats had 5/6
Sever21 [200]

Answer:

75 roasted turkeys.

Step-by-step explanation:

Ally's Eats had 75 roasted turkeys.

Bob's Goods had 4/5 as many roasted turkeys as Ally's Eats, hence, the number of roasted turkeys Bob's Goods had is:

4/5 * 75 = 60 roasted turkeys

Ally's Eats had 5/6 as many roasted turkeys as Charlotte's Market. In other words, Charlotte's market had 6/5 as many roasted turkeys as Ally's Eats:

6/5 * 75 = 90 roasted turkeys.

The average is given as the sum of all toasted turkeys in the three shops divided by 3. Hence:

A = (75 + 60 + 90) / 3

A = 225 / 3 = 75 roasted turkeys

The average number of roasted turkeys in the three shops is 75.

7 0
3 years ago
Help in this as well
Charra [1.4K]

Answer:

b 321 and 322

Step-by-step explanation:

because 321.5 is between 321 and 322

6 0
3 years ago
Is 5x+6y=1 a direct variation? (yes or no only)
aleksandr82 [10.1K]
Direct variation is y=kx
indirect variation is y=k/x

if we can get it into that form, then it is

5x+6x=1
6y=-5x+1
y=(-5/6)x+1/6
yes


-4x+9y=4
9y=4x+4
y=(4/9)x+4/8
yes

5 0
3 years ago
What is the equation of the circle that has its center at -26,120 and passed through the origin
OlgaM077 [116]

well, first off let's check those two points, we know it's centerd at (-26 , 120) and we also know it passes through (0 , 0), so the distance between those two points is its radius

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{-26}~,~\stackrel{y_2}{120})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{(~~-26 - 0~~)^2 + (~~120 - 0~~)^2} \implies r=\sqrt{(-26)^2 + (120 )^2} \\\\\\ r=\sqrt{( -26 )^2 + ( 120 )^2} \implies r=\sqrt{ 676 + 14400 } \implies r=\sqrt{ 15076 } \\\\[-0.35em] ~\dotfill

\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{-26}{h}~~,~~\underset{120}{k})}\qquad \stackrel{radius}{\underset{\sqrt{15076}}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - (-26) ~~ )^2 ~~ + ~~ ( ~~ y-120 ~~ )^2~~ = ~~(\sqrt{15076})^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (x+26)^2+(y-120)^2 = 15076~\hfill

3 0
1 year ago
What is the midpoint of the segment whose endpoints are (-6,5) and (4,-7)?
Savatey [412]
The answer would be (-1, -1) on a coordinate grid. 

(-6+4)/2=x
(-2)/2=x
-1=x

(5+-7)/2=y
(-2)/2=y
-1=y
6 0
3 years ago
Read 2 more answers
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