Answer: {x,y}={-1,2}
step-by-step explanation:
// Solve equation [2] for the variable x
[2] 2x = 5y - 12
[2] x = 5y/2 - 6
// Plug this in for variable x in equation [1]
[1] 2•(5y/2-6) + 3y = 4
[1] 8y = 16
// Solve equation [1] for the variable y
[1] 8y = 16
[1] y = 2
// By now we know this much :
x = 5y/2-6
y = 2
// Use the y value to solve for x
x = (5/2)(2)-6 = -1
Solution :
{x,y} = {-1,2}
the radius is half of the diameter, so d = 2r , or double the radius :)
