Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2
and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>
The cross product n1 x n2
vl=
i j l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>
By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.
Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t
Answer:
x = 9
Step-by-step explanation:
When doing these types of problems, the main goal is to get the variable by itself. Its kind of hard to explain with words so I will just use numbers.
15x + 14 = 149
(Subtract 14 on both sides. Remember, when you do something (Like subtracting, adding, etc.) on one side you have to do it to the other.)
15x + 14 = 149
-14 = -14
---------------------------
15x = 135
(Divide 15 on both sides. Since we need to use inverse operation to cancel the 15 out, we would divide 15 on both sides.)
15x/15 = 135/15
x = 9
Hope this helps :)
A graph and a table are provided below this discussion. You should plot these in this order.
y = 1 - 3x In red. It might be hard to see
y < 1 - 3x In blue
The table which is to the left of the graph
The table is constructed by putting a value in for x
x = 2
y = 1 - 3(2)
y = 1 - 6
y = - 5
It's easy once you spot the ones that can cross cancel!
Say we have the fractions 8/10 and 20/23.
(it's easier to see on top of each other)
If you look diagonally , so 8 and 23 and 10 and 20, you can see that 10 and 20 have a common factor. So we divide it by the highest common factor to reduce those numbers, making it easier to multiply. 10 and 20 can become 1 and 2, dividing by 10. So now we are left with 8/1 and 2/23, and now we multiply normally going across so 16/23.
This works going both diagonals and simplifying both, but in that case it would be easier to try and simplify the fractions before cross multiplying them.
Basically: look for those diagonals and if they can be divided down by the highest common factor, go for it to make it easier to multiply normally afterwards.
Hope I helped!
F(3)=5 // f(3)=2(3)-1 = 5