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NemiM [27]
3 years ago
7

Given the arithmetic sequence where an= 3 + 2(n-1), what is the domain for n?​

Mathematics
1 answer:
lakkis [162]3 years ago
4 0

Answer:

The set of all positive integers equal to or greater than 1

Step-by-step explanation:

n can take on the integer values 1 ... ∞

The formula for the nth term is a(n) = a(1) + 2(n - 1)

First term:  n = 1.  Then a(1) = 3 + 2(0) = 3 (as expected).

5th term:  n = 5.  Then a(5) = 3 + 2(5 - 1) = 3 + 8 = 11

...

and so on.

You might be interested in
(a) find parametric equations for the line of intersection of the planes x + y + z = 2 and x + 7y + 7z = 2
nlexa [21]
Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2

and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>

The cross product n1 x n2
vl=
 i  j  l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>

By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.

Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t

3 0
3 years ago
15x + 14 = 149<br><br><br>Plz solve for x
Juliette [100K]

Answer:

x = 9

Step-by-step explanation:

When doing these types of problems, the main goal is to get the variable by itself. Its kind of hard to explain with words so I will just use numbers.

15x + 14 = 149

(Subtract 14 on both sides. Remember, when you do something (Like subtracting, adding, etc.) on one side you have to do it to the other.)

15x + 14 = 149

       -14 =  -14

---------------------------

15x = 135

(Divide 15 on both sides. Since we need to use inverse operation to cancel the 15 out, we would divide 15 on both sides.)

15x/15 = 135/15

x = 9

Hope this helps :)

8 0
3 years ago
NEED HELP!!! graph <br> y&lt;1−3x
vekshin1

A graph and a table are provided below this discussion. You should plot these in this order.

y = 1 - 3x    In red. It might be hard to see

y < 1 - 3x    In blue

The table which is to the left of the graph

The table is constructed by putting a value in for x

x = 2

y = 1 - 3(2)

y = 1 - 6

y = - 5



8 0
3 years ago
How do how you cross cancel multiplying fractions
DENIUS [597]

It's easy once you spot the ones that can cross cancel!

Say we have the fractions 8/10 and 20/23. \frac{8}{10} \frac{20}{23} (it's easier to see on top of each other)

If you look diagonally , so 8 and 23 and 10 and 20, you can see that 10 and 20 have a common factor. So we divide it by the highest common factor to reduce those numbers, making it easier to multiply. 10 and 20 can become 1 and 2, dividing by 10. So now we are left with 8/1 and 2/23, and now we multiply normally going across so 16/23.

This works going both diagonals and simplifying both, but in that case it would be easier to try and simplify the fractions before cross multiplying them.

Basically: look for those diagonals and if they can be divided down by the highest common factor, go for it to make it easier to multiply normally afterwards.

Hope I helped!

5 0
3 years ago
Hey cutie pls help me thank u !!
andrey2020 [161]
F(3)=5 // f(3)=2(3)-1 = 5
6 0
3 years ago
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