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shepuryov [24]
3 years ago
12

What are the lower and upper quartiles of this data 122,164,71,98,84,147,114,111,98,85,104,71,77

Mathematics
1 answer:
RSB [31]3 years ago
7 0
Lower quartile = 80.5
Upper quartile = 118
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Question is in picture.
Norma-Jean [14]

Answer:

<h2>B. 2x + y = 4</h2>

Step-by-step explanation:

Having the system of equations in its simplest form

\left\{\begin{array}{ccc}ax+by=c\\dx+ey=f\end{array}\right

If

a=d,\ b=e,\ c=f

then the system of equations has infinitely many solutions.

If

a=d,\ b=e,\ c\neq f

then the system of equations has no solution.

If

a\neq d\ or\ b\neq e

then the system of equations has one solution.

We have the equation

y=-2x+4

Convert to the standard form Ax + By = C<em>:</em>

<em />y=-2x+4<em>              add 2x to both sides</em>

y+2x=-2x+2x+4\\\\2x+y=4

3 0
3 years ago
A dance school has 63 ballet dancers a 42% of the total number of dancers in the score ballet dancers what is the total number o
melamori03 [73]
42% of what is 63

0.42x = 63
x = 63/0.42
x = 150

There are 150 dancers in the school
3 0
3 years ago
Gary is trying to find the height of a mountain he knows he is standing about (see picture)
QveST [7]

Answer:

stop telling people to do your homework on canvas!

Step-by-step explanation:

6 0
3 years ago
The focus of a parabola is (-4, -5), and its directrix is y = -1. Fill in the missing terms and signs in the parabola's equation
Marizza181 [45]

Answer:

(x+4)^2=-8(y+3)

Step-by-step explanation:

Given:

focus of parabola=(-4,-5)

directrix= -1

Standard form of parabola :

(x - h)^2 = 4p (y - k),

where focus is:

(h, k + p)

directrix  is :

y = k - p

Now equating the values we get

(-4,-5) = (h,k+p)

h=-4

k+p=-5

k=-5-p

Also

y=-1 and y=k-p

i.e. k-p=-1

Substituting k=-5-p in above we get:

-5-p-p=-1

-2p=-1+5

p=4/-2

p=-2

Putting p=-2 in k-p=-1 we get:

k=-1-2

k=-3

Putting all the values in standard formula for parabola we get:

(x - (-4))^2 = 4(-2) (y -(-3))

(x+4)^2=-8(y+3)!

3 0
3 years ago
Find four consecutive odd integers such that the sum of the first three exceeds the fourth by 18?
Stolb23 [73]

Let, numbers = x,(x+2),(x+4),(x+6)

A.T.Q,

x+x+2+x+4 = x+6+18

3x+6 = x+24

3x-x= 24-6

2x = 18

x = 9

Numbers would be 9, 11, 13, 15

6 0
3 years ago
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