All categories

3 years ago

Prove this ~ cosx/1-tanx + sinx/1-cotx = cosx + sinx

Mathematics

1 answer:

bearhunter [10]3 years ago

3 0

The solution is attached in the image below. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

You might be interested in

Which is the best estimate for the length of a lady bug?

Effectus [21]

Answer:

The average length of a ladybug is . 3 to . 4 inches.

7 0

3 years ago

What is the inverse of f(x)=x^2+5 and is it a function?

Alla [95]

Answer:hello :

let : y = f(x)

you have : y = x² + 5

calculate : x

x² = y - 5

x exsit for : y - 5 ≥ 0

if : x ≥ 0 x = √( y - 5) so the inverse functio for f is : g(x) = √( x - 5)

if : x ≤ 0 x = - √( y - 5) so the inverse functio for f is :h(x) = - √( x - 5)

8 0

3 years ago

Suppose that there are 20 numbers in a data set and that they are all different. How many of the values in this data set are bet

antoniya [11.8K]

Answer:

10 Values

Step-by-step explanation:

We would use a set of data for illustration

Given the set of numbers:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20

Since we have an even number of data, the median is in between 10 and 11.

(1,2,3,4,5,6,7,8,9,10),(11,12,13,14,15,16,17,18,19,20)

Lower Half: (1,2,3,4,5,6,7,8,9,10)

The median of the lower half is in between 5 and 6. So $Q_1$ is in between 5 and 6.

Upper Half:(11,12,13,14,15,16,17,18,19,20)

The median of the upper half is in between 15 and 16. So $Q_3$ is in between 15 and 16.

Therefore, we have the [position of the first and third quartiles as:

1,2,3,4,5, $Q_1$ ,6,7,8,9,10,11,12,13,14,15, $Q_3$ ,16,17,18,19,20

There are 10 values in between the first and third quartiles.

7 0

3 years ago

The count in a bacteria culture was 800 after 15 minutes and 1200 after 40 minutes. Assuming the count grows exponentially,

Maslowich

Answer:1) bacteria size = b(initial) * e^(r * t)

initial size = 300

final size = 1600.

Substituting the values into the main equation:

1600 = 300 * e^(r * 35 - 20)

solving for 'r'.

1600 = 300 * e^(r * 15)

1600/300 = e^(r * 15)

taking natural log on both sides to eliminate the power

ln(16/3) = ln[e^(r * 15)]

ln(16/3) = r * 15

r = ln(16/3) / 15

= 0.11159843

= 11.16%

To find the initial bacteria size,

Given: t = 20

300 = b * e^(0.1116 * 20)

Solving for b:

300 = b * e^2.232

b = 300/e^2.232

b = 32

Step-by-step explanation:

3 0

3 years ago

A bag contains 30 cookies: 9 vanilla, 9 chocolate, and 12 oatmeal. What is the probability that a chocolate is randomly selected

telo118 [61]

There is 9 chocolate cookies, so the probability of choosing chocolate is $\frac{9}{30}$ . We then simplify to get $\frac{3}{10}$ , or 0.3.

3 0

3 years ago