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4vir4ik [10]
3 years ago
15

Prove this ~ cosx/1-tanx + sinx/1-cotx = cosx + sinx

Mathematics
1 answer:
bearhunter [10]3 years ago
3 0

The solution is attached in the image below. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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A line has a slope of zero and passes through the point (-2, 3). Which of the following points must also lie on the line?
brilliants [131]

Answer:

(5,3)

Step-by-step explanation

Because the slope is 0, it means its a horizontal line. because the horizontal is on 3, then it doesnt  matter what x is as long as y is 3 if that makes any sense.

7 0
3 years ago
What is the distance between points a and e
kozerog [31]
Please post the question with an attachment of what you want to be answered next time.
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2 years ago
30 Points!!! Please help!! Will give Brainliest!! Please...
AlekseyPX

Answer:

11

Step-by-step explanation:

Opposite sides are congruent at parallelograms. So x+16 must be equal to 2x+5. Solve the equation;

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2 years ago
Pick all the names for this shape.
Nutka1998 [239]

Answer:

quadrilateral \\ rectangle \\ parallellogram \\  \\  \\  \\ all \: the \: three \: except \: square..

8 0
3 years ago
Find the equation of each line with the following general informatie (c) r-intercept a and slope m (d) inclination and y-interce
VikaD [51]

Let's use the slope-intercept equation:

\begin{gathered} y=mx+b \\ m=slope \\ b=y-intercept \\ x-intercept=a \\ x=\frac{y-b}{m} \\ x=\frac{y}{m}-\frac{b}{m} \\ x=\frac{y}{m}-a \\ or \\ y=mx+ma=m(x+a) \end{gathered}

------------------------------------

d)

\begin{gathered} y=mx+b \\ m=slope=\theta \\ b=y-intercept \\ y=\theta x+b \\  \end{gathered}

6 0
10 months ago
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