Hello :
<span>the nth term in a geometric sequence where is ;
an = a1 ×qn .... q : common ratio a1 the first term
exempl :
C) an = 2×3^n-1
an =2×3^n ×3^-1
an =(2/3)×3^n
a1 = 2/3 and q= 3
same method for : D
</span>
Answer:
-2, -4, -3 + 2i, -3-2i
Step-by-step explanation:
Equaling the function to zero we have:
(x ^ 2 + 6x + 8) (x ^ 2 + 6x + 13) = 0
For the first parenthesis we have:
(x ^ 2 + 6x + 8) = 0\\(x + 4) (x + 2) = 0
Therefore the roots are:
x = - 4\\x = - 2
For the second parenthesis we have:
(x ^ 2 + 6x + 13) = 0
By completing squares we have:
x ^ 2 + 6x = -13
x ^ 2 + 6x + (\frac{6}{2}) ^ 2 = -13 + (\frac{6}{2}) ^ 2\\x ^ 2 + 6x + 9 = -13 + 9\\(x + 3) ^ 2 = - 4\\x + 3 = +/- \sqrt{-4}
Therefore the roots are:
x = -3 + 2i\\x = -3 - 2i
Hope this was helpful
Hey there!
We want to multiply a certain quantity by 2, so we will put the two outside of parentheses and put our variable (x) minus two inside the parentheses to represent this. This will all equal two.
2(x-6)=2
The unknown number is also 7.
I hope that this helps!
Answer:
44
Step-by-step explanation:
