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N76 [4]
3 years ago
13

Consider circle T with radius 24 in. and θ = StartFraction 5 pi Over 6 EndFraction radians. Circle T is shown. Line segments S T

and V T are radii with lengths of 24 inches. Angle S T V is theta. What is the length of minor arc SV?
Mathematics
2 answers:
k0ka [10]3 years ago
6 0

Answer:

<h2>20π in</h2>

Step-by-step explanation:

Length of an arc is expressed as L = \frac{\theta}{2\pi }  *  2\pi r\\. Given;

\theta = \frac{5\pi }{6} rad\\ radius = 24in\\

The length of the minor arc SV is expressed as:

L = \frac{\frac{5\pi }{6} }{2\pi }  *  2\pi (24)\\L = \frac{5\pi }{12\pi } * 48\pi \\L = \frac{5}{12} * 48\pi  \\L = \frac{240\pi }{12} \\L = 20\pi \ in

Hence, The length  of the arc SV is 20π in

Juliette [100K]3 years ago
3 0

Answer:

20 pi

Step-by-step explanation:

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