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Nata [24]
3 years ago
10

Find the approximate value of the circumference of a circle with the given radius. Use = 3.14. Round your results to one more de

cimal than in the given radius.
4 inches

C =
Mathematics
2 answers:
AleksandrR [38]3 years ago
8 0
I got  25.12 but the second I did the problem I got 23.12 but then I did it again and got  25.12 so go with  25.12
xxTIMURxx [149]3 years ago
4 0
The circumference of this circle is about 25.12 inches. Hope you get it!
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Helppppp how do u do this????
otez555 [7]
Lets x to be number of students.

1) If each students get 3 ml, then all students get 3x ml.
There was  n ml.
(n-3x) ml leftover

n - 3x = 5

2) If each students get 4 ml. 
then  all students get 4x ml.

n+21 = 4x

3)
   n - 3x = 5
- (n+21 = 4x) ------->   -n -21=-4x

n - 3x = 5
<span>-n -21= - 4x
</span>-3x-21=5 - 4x
x=5+21
x=26 

 Answer : 26 students

Check:
x=26, n-3x = 5, n-3*26=5, n=83
n+21 = 4x
83+21=4*26
104 = 104 true



7 0
3 years ago
Whats the perimeter of this small parallelogram?
Arisa [49]

Answer:

Perimeter = 18 units

Step-by-step explanation:

one side = 4

other side²  = 3² + 4² + 25

other side = √25 = 5

Perimeter = (2 x 4) + (2 x 5) = 18 units

4 0
3 years ago
Please help me with this.
vitfil [10]

Answer:

15.6 inches

Step-by-step explanation:

Here we want to find the length of the missing side

Mathematically, we can use Pythagoras’ theorem

The theorem states that the square of the hypotenuse equals the sum of the squares of the two other sides

Let the missing side be x

18 is the side that faces right angle and this is the hypotenuse

Thus, we have ;

x^2 + 9^2 = 18^2

x^2 = 324 - 81

x^2 = 243

x = √(243)

x = 15.6 in

5 0
3 years ago
Math be like 0-0????
pashok25 [27]

Answer:  A & C

<u>Step-by-step explanation:</u>

HL is Hypotenuse-Leg

A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

   a leg from ΔABC ≡ a leg from ΔFGH

   Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

B) a leg from ΔABC ≡ a leg from ΔFGH

   the other leg from ΔABC ≡ the other leg from ΔFGH

   Therefore LL (not HL) Congruency Theorem can be used.

C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

   at least one leg from ΔABC ≡ at least one leg from ΔFGH

   Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

D) an angle from ΔABC ≡ an angle from ΔFGH

   the other angle from ΔABC ≡ the other angle from ΔFGH

   AA cannot be used for congruence.

5 0
4 years ago
Order these weights from lightest to heaviest 10 ounces 1 pond and 1 ounce
Alchen [17]
1 ounce, 10 ounces, 1 pound.

1 pound = 16 ounces
6 0
3 years ago
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