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Lisa [10]
3 years ago
15

Using the factoring process, what constant is added to the right side of the quadratic equation 3x2+4x+_=1+_ in order to solve b

y completingredients the square?
Mathematics
1 answer:
yan [13]3 years ago
4 0
Group and factor out the linear coefient
(3x^2+4x)+?=1+????
3(x^2+4/3x)+?=1+????
4/3 divided by 2 is 2/3
2/3 squared is 4/9
add negative and negative inside
3(x^2+4/3x+4/9-4/9)+?=1+????
factor perfect square
3((x+2/3)^2-4/9)+?=1+????
distribute
3(x+2/3)^2-4/3+?=1+????
add 4/3 to both sides
3(x+2/3)^2+?=7/3+????
minus? from both sides
3(x+2/3)^2=7/3+????-?
dunno what missing number is, maybe
hmm
4/9 times 3=4/3
the missing number is 4/3
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After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e
Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in \mu g/mL

C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})

Thus, we are given the time interval [0,12] for t.

  • We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
  • The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})

Equating the first derivative to zero, we get,

\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0

Solving, we get,

8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2

At t = 0

C(0) = 8(e^{(0)}-e^{(0)}) = 0

At t = 2

C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185

At t = 12

C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

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3 years ago
Which expressions are equivalent to the given expression? ​
expeople1 [14]

Answer:

It is the 2nd answer choice 4 check 5

Step-by-step explanation:

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*PLEASE HELP ME* (math attachment) IT'S PAST MIDNIGHT I'M TIRED AND DESPERATE
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<h3><u>Answer:</u></h3>

D

<h3><u>Step-by-step explanation:</u></h3>

let's rewrite this

x + y = 11                  <em>- equation 1</em>

   - x = - y - 9           <em>- equation 2</em>

solve the first equation for x

x + y = 11            (add -y to both sides to get x by itself)

     x = -y + 11          <em> - equation 3</em>

now substitute -y + 11 for x in the second equation

 y - 11 = - y - 9        (2 negative signs next to each other equals positive)

2y - 11 = -9              (add y to both sides)

      2y = 2               (add 11 to both sides)

        y = 1                (divide both sides by 2)

now substitute y = 1 into equation 3

x = -1 + 11

x = 10

therefore, x = 10 and y = 1. in coordinates, x goes before y

therefore, the coordinates are (10, 1)

therefore the answer is D

good luck my friend! hope this helped a lot! also, i found a website if you don't fully understand this, its called MathPapa, i didn't use it to work this out so my working might be different but it definitely helps me sometimes. for an equation like this, type it likes this: x+y=11; -x=-y-9

-cheesetoasty

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Answer:

36

Step-by-step explanation:

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