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Lisa [10]
3 years ago
15

Using the factoring process, what constant is added to the right side of the quadratic equation 3x2+4x+_=1+_ in order to solve b

y completingredients the square?
Mathematics
1 answer:
yan [13]3 years ago
4 0
Group and factor out the linear coefient
(3x^2+4x)+?=1+????
3(x^2+4/3x)+?=1+????
4/3 divided by 2 is 2/3
2/3 squared is 4/9
add negative and negative inside
3(x^2+4/3x+4/9-4/9)+?=1+????
factor perfect square
3((x+2/3)^2-4/9)+?=1+????
distribute
3(x+2/3)^2-4/3+?=1+????
add 4/3 to both sides
3(x+2/3)^2+?=7/3+????
minus? from both sides
3(x+2/3)^2=7/3+????-?
dunno what missing number is, maybe
hmm
4/9 times 3=4/3
the missing number is 4/3
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user100 [1]

Answer:

117

Step-by-step explanation:

Given the expression

r³ - 2s ← substitute given values into the expression

= 5³ - 2(4)

= 125 - 8

= 117

6 0
3 years ago
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The ratio of irises to The ratio of irises to roses in Nikki's garden is 2:5. She currently has 25 roses. She is planning to add
denpristay [2]
If the proportion of iris to roses in Nikki's garden is 2: 5, it means that for 25 roses: (2/5) = (10/25). Therefore to maintain the proportion by adding 20 roses: (2/5) = (18/45). The number of irises after the addition of roses will be 10 + 18 = 28 irises.
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3 years ago
Give two examples of line segments that will make a triangle ?
77julia77 [94]

Answer:

If the length of any one side is greater than the sum of the length of the other two, the line segments cannot be used to create a triangle. It is possible to create a triangle using 3 line segments if the sum of the lengths of any two line segments is greater than the length of the third.

7 0
2 years ago
What is the perimeter of △ABC?
timofeeve [1]
<h3>Given</h3>
  • ΔABC
  • A(-3, -1), B(0, 3), C(1, 2)
<h3>Find</h3>
  • the length of the perimeter of ΔABC to the nearest tenth
<h3>Solution</h3>

The perimeter of a triangle is the sum of the lengths of its sides. The length of each side can be found using the Pythagorean theorem. Effectively, each pair of points is treated as the end-points of the hypotenuse of a right triangle with legs parallel to the x- and y-axes. The leg lengths are the differences betweeen the x- and y- coordinates of the points.

The difference of the x-coordinates of segment AB are 0-(-3) = 3. The y-coordinate difference is 3-(-1) = 4. So, the leg lengths of the right triangle whose hypotenuse is segment AB are 3 and 4. The Pythagorean theorem tells us

... AB² = 3² +4² = 9 +16 = 25

... AB = √25 = 5

You may recognize this as the 3-4-5 triangle often introduced as one of the first ones you play with when you learn the Pythagorean theorem.

LIkewise, segment AC has coordinate differences of ...

... C - A = (1, 2) -(-3, -1) = (4, 3)

These are the same leg lengths (in the other order) as for segment AB, so its length is also 5.

Segment BC has coordinate differences ...

... C - B = (1, 2) -(0, 3) = (1, -1)

The length of the line segment is figured as the root of the sum of squares, even though one of the coordinate differences is negative. The leg lengths of the right triangle used for finding the length of BC are the absolute value of these differences, or 1 and 1. Then the length BC is

... BC = √(1² +1²) = √2 ≈ 1.4

So the perimeter of the triangle ABC is

... AB + BC + AC = 5 + 1.4 + 5 = 11.4 . . . . perimeter of ∆ABC in units

_____

Please be aware that the advice to "round each step" is <em>bad advice,</em> in general. For real-world math problems, you only round the final result. You always carry at least enough precision in the numbers to ensure that there will not be any error in the final rounding.

In this problem, the only number that is not an integer is √2, so it doesn't really matter.

7 0
3 years ago
PLEASE HELP (100 POINTS)
Artyom0805 [142]

\\ \rm\Rrightarrow f(x)=-5cos\dfrac{x}{2}+5

Compare to standard equation of SHM

\\ \rm\Rrightarrow y=Acos(\omega x+\phi)

Here

  • Amplitude=A=-5

\\ \rm\Rrightarrow \omega x=\dfrac{x}{2}

\\ \rm\Rrightarrow \omega=1/2

Well the above one are for extra knowledge .

Solution:-

\\ \rm\Rrightarrow 10=-5cos\dfrac{x}{2}+5

\\ \rm\Rrightarrow 10-5=-5cos\dfrac{x}{2}

\\ \rm\Rrightarrow 5=-5cos\dfrac{x}{2}

\\ \rm\Rrightarrow cos\dfrac{x}{2}=-1

\\ \rm\Rrightarrow \dfrac{x}{2}=cos^{-1}(-1)

\\ \rm\Rrightarrow \dfrac{x}{2}=\pi

\\ \rm\Rrightarrow x=2\pi

So.

\\ \rm\Rrightarrow x=2\pi+2\pi n

3 0
2 years ago
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