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weqwewe [10]
3 years ago
12

(6k^4-k^3-8k)-(5k^4+6k-8k^3)​

Mathematics
2 answers:
Crazy boy [7]3 years ago
4 0

Answer:

( 6 4 − 1 3 − 8 ) − 1 ( 5 4 + 6 − 8 3 )

Step-by-step explanation:

Rearrange terms

( 6 4 − 1 3 − 8 ) − 1 ( 5 4 + 6 − 8 3 )    ( 6 4 − 1 3 − 8 ) − 1 ( 5 4 − 8 3 + 6 )

distribute

(6 4 − 1 3 − 8 ) − 1 ( 53   4 − 8 3 + 6 )     (6 4 − 1 3 − 8 ) − 5 4+ 8 3 − 6  

Eliminate redundant parentheses        

combine like terms

multiply like 1

solution: 4 + 7 3 − 1 4                                                                                    

DerKrebs [107]3 years ago
3 0

Answer:

9y⁴−9y

Step-by-step explanation:

Subtract 8y48y4 from 5y45y4.

6y4−y−8y−(−3y4)6y4-y-8y-(-3y4)

Multiply −3-3 by −1-1.

6y4−y−8y+3y46y4-y-8y+3y4

Simplify by adding terms.

Add 6y46y4 and 3y43y4.

9y4−y−8y9y4-y-8y

Subtract 8y8y from −y-y.

9y⁴−9y

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An observer at the top of a 532 foot cliff measures the angle of depression from the top of the cliff to a point on the ground t
Over [174]

Answer:

Distance from the base of the cliff to the point on the ground = 7608 feet

Step-by-step explanation:

Given: Height of the cliff is 532 feet, angle of depression from the top of the cliff to a point on the ground is equal to 4 degrees.

To find: distance from the base of the cliff to the point on the ground

Solution:

In ΔABC,

\angle ACB=4^{\circ}  (Alternate interior angles)

For any angle \theta, \tan \theta = side opposite to angle/side adjacent to angle

\tan C=\frac{AB}{BC}

Put AB=532\,,\,\angle C=4^{\circ}

\tan 4^{\circ}=\frac{532}{BC}\\\\BC=\frac{532}{\tan 4^{\circ}}\\\\=7607.95\\\\\approx 7608\,\,feet

Distance from the base of the cliff to the point on the ground = 7608 feet

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5 0
3 years ago
Simply 10^0 0 is exponent
hjlf

Answer:

1

Step-by-step explanation:

any number to the power of 0 is 1 :)

7 0
2 years ago
Read 2 more answers
Elena randomly chooses a number from 1 to 10. What is the probability she chooses a number greater than 5?
zepelin [54]

ANSWER

P(E)=\frac{1}{2}

EXPLANATION

From the given information, Elena chooses a number from 1 to 10.

The sample space is

S={1,2,3,4,5,6,7,8,9,10}

n(S)=10

The numbers greater than 5 are:

E={6,7,8,9,10}

n(E)=5

The probability that, she chooses a number greater than 5 is:

P(E) =  \frac{n(E)}{n(S)}

Substitute the values,

P(E) =  \frac{5}{10}

P(E) =  \frac{1}{2}

5 0
2 years ago
Five years after 650 high school seniors graduated, 400 had college degree and 310 were married. Half of the students with a col
nalin [4]
I THINK THE ANSWER IS -70 I THINK

3 0
3 years ago
I think its C, not sure
Alona [7]
Yes; you are correct.
___________________________________________________
The correct answer is:
___________________________________________________
Answer choice:  [C]:  " x³ − 9x² + 23x <span>− 12 " .
___________________________________________________
Note: (a </span>− b) (c − d + e) = ac − ad + ae − bc + bd − be ;
___________________________________________________
          (x − 4) (x² <span>− 5x + 3) = 

   x * x</span>² = x³ <span>− 

   x * 5x = 5x</span>² + 

   x * 3   = 3x <span>−

   4 * x</span>²  = 4x² <span>−

   -4 * 5x =  -20x +

   -4 * 3 =  -12; 
________________________________________
</span>          (x − 4) (x² − 5x + 3) = 

x³ − 5x² + 3x −4x² − (-20x) + (-12) ;

=  x³ − 5x² + 3x −4x² + 20x − 12 ;

= x³ − 5x² − 4x² + 3x + 20x − 12 ;

= x³ − 9x²  + 23x − 12 ;  which is:
__________________________________________________
Answer choice:  [C]:  " x³ − 9x²  + 23x − 12 " .
__________________________________________________
7 0
3 years ago
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