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Mariulka [41]
3 years ago
12

0.86421 . . . is an irrational number. true false

Mathematics
2 answers:
Ad libitum [116K]3 years ago
7 0
Numbers that cannot be expressed as an exact ratio are called irrational numbers so that would make it true
Andreyy893 years ago
5 0
If that decimal doesn't terminate, then it is an irrational number.
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\large{\color{red}{\rightarrow{-\:0.2}}}

3 0
2 years ago
Which of the following explains the relationship between angles B and C? Lines JK and JM intersect at point J, creating four ang
zhenek [66]

Answer:

Adjacent angles

4 0
3 years ago
Read 2 more answers
Help please!!!!!!!!!!!!! Explain if possible
iris [78.8K]
Answer is C.
For every option, sub in the value and find the answer that matches the equation!

Example for option A, F(x) = x + 4 and G(x) = x²
G(F(x)) = G(x + 4) ーー> sub in the value of F(x)
Let's take the subbed in value, (x + 4) as x, and this x will be the x for G(x).

∴ Since G(x) is x²
G(x + 4) = (x + 4)² ーー> remember (x + 4) is represented as x.
= x² + 16
∴ You know that the answer is not A, do this for all options and you'll find the answer, C!

4 0
3 years ago
-7 \times (7 + 9)−7×(7+9)
prisoha [69]

Answer:

−224

Step-by-step explanation:

−7(7+9)−7(7+9)

=(−7)(16)−7(7+9)

=−112−7(7+9)

=−112−(7)(16)

=−112−112

=−224

8 0
3 years ago
A chemical factory has 2 cylindrical chemical tanks, one containing Chemical X and the other containing Chemical Y. The tank con
Mashutka [201]
The tank with Chemical X "takes up" a space of 25ft³.  Ordinarily we think of something "taking up" space as being area or surface area; however, area is a square measurement, and this is cubic; this must be volume.  The volume of the tank with Chemical X is 1.5 times the volume of the tank containing Chemical Y; setting this up in an equation we would have
25 = 1.5<em>V</em>
We would divide both sides by 1.5 to get the volume of the tank containing Chemical Y:
\frac{25}{1.5}=\frac{1.5V}{1.5} \\16 \frac{2}{3}=V
To find the volume of a cylinder, we find the base area and multiply by the height.  We know the volume and we know the base area, so our equation to find the height of the tank containing Chemical Y would look like:
16 \frac{2}{3}=3.2h \\ 16 \frac{2}{3}=3 \frac {2}{10}h
We would now divide both sides by 3 2/10:
\frac{16 \frac{2}{3}}{3 \frac{2}{10}}= \frac{3 \frac{2}{10}h}{3 \frac{2}{10}}
This is the same as:
\frac{\frac{50}{3}}{\frac{32}{10}}=h \\ \\ \frac{50}{3}* \frac{10}{32}=h \\ \\ \frac{500}{96}
So the height of the tank containing Chemical Y is 500/96 = 5 5/24 feet.
8 0
3 years ago
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