Answer:
The amount in the account after six years is $2,288.98
Step-by-step explanation:
In this question, we are asked to calculate the amount that will be in an account that has a principal that is compounded quarterly.
To calculate this amount, we use the formula below
A = P(1+r/n)^nt
Where P is the amount deposited which is $1,750
r is the rate which is 4.5% = 4.5/100 = 0.045
t is the number of years which is 6 years
n is the number of times per year, the interest is compounded which is 4(quarterly means every 3 months)
we plug these values into the equation
A = 1750( 1 + 0.045/4)^(4 * 6)
A = 1750( 1 + 0.01125)^24
A = 1750( 1.01125)^24
A = 2,288.98
The amount in the account after 6 years is $2,288.98
We know that
case 1)
Applying the law of sines
a/Sin A=b/Sin B
A=56°
a=12
b=14
so
a*Sin B=b*Sin A----> Sin B=b*Sin A/a---> Sin B=14*Sin 56°/12
Sin B=0.9672
B=arc sin (0.9672)------> B=75.29°-----> B=75.3°
find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+75.3)----> C=48.7°
find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 48.7°/Sin 56°)
c=10.87-----> c=10.9
the answer Part 1)
the dimensions of the triangle N 1
are
a=12 A=56°
b=14 B=75.3°
c=10.9 C=48.7°
case 2)
A=56°
a=12
b=14
B=180-75.3----> B=104.7°
find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+104.7)----> C=19.3°
find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 19.3°/Sin 56°)
c=4.78-----> c=4.8
the answer Part 2)
the dimensions of the triangle N 2
are
a=12 A=56°
b=14 B=104.7°
c=4.8 C=19.3°
