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2 years ago

If 30.s g of milk contains 18 C, how many

Mathematics

2 answers:

liubo4ka [24]2 years ago

8 0

Answer:

the answer would be (244/30.5) x 18, so the answer should be 144!

Step-by-step explanation:

Put me the brainest. thanks

AleksandrR [38]2 years ago

3 0

If 30.5 g contains 18 cal then
30.5÷18 would tell how much calories are in 1 g which is 1.6944.
therefore to find how much would be in 244 g you would multiply 244 by 1.6944 which would be 413.4 calories

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A certain right triangle has area 30 in. squared . one leg of the triangle measures 1 in. less than the hypotenuse. let x repres

Brut [27]

A) The length of the longer leg is x-1

b) Based on the area, the other leg is 2*30/(x -1). Based on the Pythagorean theorem, the other leg is √(x^2 -(x -1)^2).

c) Equating the two expressions for the shorter leg, we have
.. 60/(x -1) = √(2x -1)
.. 3600/(x -1)^2 = (2x -1)
.. (2x -1)(x^2 -2x +1) = 3600
.. 2x^3 -5x^2 +4x -3601 = 0

d) There is one positive real root, at x=13. A graphical solution works well.

The three sides of the triangle are 5 in, 12 in, 13 in.

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3 years ago

Julio signs a new lease for $800 and in the agreement the complex will raise his rent 3% each year that he renews. As of right n

Sholpan [36]

D because it does not specify when he would buy a house

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3 years ago

Factor completely

luda_lava [24]

Answer:

Step-by-step explanation:

1. $7x^3y+14x^2y^3-7x^2y^2$

The GCF of all the term of the above polynomial is $7x^2y$ , hence we take it outside and form a bracket

$7x^2y(x+2y^2-y)$

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

2. $5x(x+3)+6(x+3)$

The GCF of all the term of the above polynomial is $(x+3)$ , hence we take it outside and form a bracket

$(x+3)(5x+6)$

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

3. $8x^5+2x^4+4x^2$

The GCF of all the term of the above polynomial is $2x^2$ , hence we take it outside and form a bracket

$2x^2(4x^3+x^2+2)$

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (D) is the right answer

4 0

3 years ago

A random experiment was conducted where a Person A tossed five coins and recorded the number of ""heads"". Person B rolled two d

cestrela7 [59]

Answer:

(10) Person B

(11) Person B

(12) $P(5\ or\ 6) = 60\%$

(13) Person B

Step-by-step explanation:

Given

Person A $\to$ 5 coins (records the outcome of Heads)

Person $\to$ Rolls 2 dice (recorded the larger number)

Person A

First, we list out the sample space of roll of 5 coins (It is too long, so I added it as an attachment)

Next, we list out all number of heads in each roll (sorted)

$Head = \{5,4,4,4,4,4,3,3,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2,2,2,1,1,1,1,1,0\}$

$n(Head) = 32$

Person B

First, we list out the sample space of toss of 2 coins (It is too long, so I added it as an attachment)

Next, we list out the highest in each toss (sorted)

$Dice = \{2,2,3,3,3,3,4,4,4,4,4,4,5,5,5,5,5,5,5,5,6,6,6,6,6,6,6,6,6,6\}$

$n(Dice) = 30$

Question 10: Who is likely to get number 5

From person A list of outcomes, the proportion of 5 is:

$Pr(5) = \frac{n(5)}{n(Head)}$

$Pr(5) = \frac{1}{32}$

$Pr(5) = 0.03125$

From person B list of outcomes, the proportion of 5 is:

$Pr(5) = \frac{n(5)}{n(Dice)}$

$Pr(5) = \frac{8}{30}$

$Pr(5) = 0.267$

From the above calculations:  $0.267 > 0.03125$  Hence, person B is more likely to get 5

Question 11: Person with Higher median

For person A

$Median = \frac{n(Head) + 1}{2}th$

$Median = \frac{32 + 1}{2}th$

$Median = \frac{33}{2}th$

$Median = 16.5th$

This means that the median is the mean of the 16th and the 17th item

So,

$Median = \frac{3+2}{2}$

$Median = \frac{5}{2}$

$Median = 2.5$

For person B

$Median = \frac{n(Dice) + 1}{2}th$

$Median = \frac{30 + 1}{2}th$

$Median = \frac{31}{2}th$

$Median = 15.5th$

This means that the median is the mean of the 15th and the 16th item. So,

$Median = \frac{5+5}{2}$

$Median = \frac{10}{2}$

$Median = 5$

Person B has a greater median of 5

Question 12: Probability that B gets 5 or 6

This is calculated as:

$P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}$

From the sample space of person B, we have:

$n(5\ or\ 6) =n(5) + n(6)$

$n(5\ or\ 6) =8+10$

$n(5\ or\ 6) = 18$

So, we have:

$P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}$

$P(5\ or\ 6) = \frac{18}{30}$

$P(5\ or\ 6) = 0.60$

$P(5\ or\ 6) = 60\%$

Question 13: Person with higher probability of 3 or more

Person A

$n(3\ or\ more) = 16$

So:

$P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Head)}$

$P(3\ or\ more) = \frac{16}{32}$

$P(3\ or\ more) = 0.50$

$P(3\ or\ more) = 50\%$

Person B

$n(3\ or\ more) = 28$

So:

$P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Dice)}$

$P(3\ or\ more) = \frac{28}{30}$

$P(3\ or\ more) = 0.933$

$P(3\ or\ more) = 93.3\%$

By comparison:

$93.3\% > 50\%$

Hence, person B has a higher probability of 3 or more

7 0

2 years ago

A town's yearly snowfall in inches over a 10-year period is recorded in this table. What is the mean of the snowfall amounts? 15

Alexandra [31]

The answer is 17.9 in. mean snowfall over a 10-year period.

3 0

3 years ago

Read 2 more answers