Answer:
(27.3692 ; 44.6308)
Step-by-step explanation:
Mean, xbar = 36
Standard deviation, s = 11
Sample size, n = 12
Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718
Confidence interval :
Xbar ± Margin of error
Margin of Error = Tcritical * s/sqrt(n)
Margin of Error = 2.718 * 11/sqrt(12) = 8.6308
Confidence interval :
Lower boundary : 36 - 8.6308 = 27.3692
Upper boundary : 36 + 8.6308 = 44.6308
(27.3692 ; 44.6308)
y=mx+b
since the b is 0, the formula is y= -3x
Answer:
3x−2y=12
Solve for y
.
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Subtract 3x
from both sides of the equation.
−2y=12−3x
Divide each term by −2
and simplify.
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y=−6+3x2
Rewrite in slope-intercept form.
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The slope-intercept form is y=mx+b
, where m is the slope and b
is the y-intercept.
y=mx+b
Reorder −6
and 3x2
.
y=3x2−6
Rewrite in slope-intercept form.
y=32x−6
Use the slope-intercept form to find the slope and y-intercept.
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Find the values of m
and b using the form y=mx+b
.
m=32
b=−6
The slope of the line is the value of m
, and the y-intercept is the value of b
.
Slope: 32
Y-Intercept: −6
Any line can be graphed using two points. Select two x
values, and plug them into the equation to find the corresponding y
values.
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Choose 0
to substitute in for x
to find the ordered pair.
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(0,−6)
Choose 1
to substitute in for x
to find the ordered pair.
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(1,−92)
Create a table of the x
and y
values.
xy0−61−92
Graph the line using the slope and the y-intercept, or the points.
Slope: 32
Y-Intercept: −6
xy0−61−92
