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Mamont248 [21]
3 years ago
7

The table represents the number of cheese crackers in the lunchboxes of 9 boys and 9 girls. By looking at the table, does it app

ear that the degree of variability for the boys' data is greater, less, or the same as the girls' data? Compute the interquartile range of each data set. Using the interquartile range, compare the degree of variability between the data sets. Explain how the comparison supports your first answer.
A) no; Boys: IQR: 4.5; Girls IQR: 3; The degree of variability for both sets is about the same.
B) no; Boys: IQR: 3; Girls IQR: 4.5; The degree of variability for both sets is about the same.
C) yes; Boys: IQR: 8; Girls IQR: 5; The degree of variability is greater for the boys than for the girls.
D) yes; Boys: IQR:10; Girls IQR:16; The degree of variability for the boys is less than for the boys.
Mathematics
2 answers:
mariarad [96]3 years ago
7 0

Answer:A)

Step-by-step explanation:

I got it wrong for you, lol. sorry im so late but i was looking for this awnser two.

Westkost [7]3 years ago
5 0
CAN SOMEONE PLEASE ANSWER IT RIGHT NOW I NEED IT!!
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She would’ve ran 6 miles in an hour.
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Match each equation with its solution set.
taurus [48]

Answer:

1- The solution of I2x + 5I = 9 is {-7 , 2}

2- The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- The solution of I5 - xI = 6 is {-1 , 11}

4- The solution of I6x - 8I + 7 = 5 is ∅

5- The solution of Ix + 3I = 12 is {-15 , 9}

6- The solution of Ix - 3I = -12 is ∅

Step-by-step explanation:

* At first lets explain the meaning of IxI = a

- If IxI = a ⇒ then x = a or x = -a

- IxI never give a negative answer, because IxI means the

 magnitude of x is always positive

Ex: I-2I is 2

* Now lets find the solution of each equation

1- ∵ I2x + 5I = 9

∴ 2x + 5 = 9 ⇒ subtract 5 from both sides

∴ 2x = 4 ⇒ divide both sides by 2

∴ x = 2

OR

∴ 2x + 5 = -9 ⇒ subtract 5 from both sides

∴ 2x = -14 ⇒ divide both sides by 2

∴ x = -7

* The solution of I2x + 5I = 9 is {-7 , 2}

2- ∵ I2x + 7I + 2 = 11 ⇒ Subtract 2 from both sides

∴ I2x + 7I = 9

∴ 2x + 7 = 9 ⇒ subtract 7 from both sides

∴ 2x = 2 ⇒ divide both sides by 2

∴ x = 1

OR

∴ 2x + 7 = -9 ⇒ subtract 7 from both sides

∴ 2x = -16 ⇒ divide both sides by 2

∴ x = -8

* The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- ∵ I5 - xI = 6

∴ 5 -x = 6 ⇒ subtract 5 from both sides

∴ -x = 1 ⇒ divide both sides by -1

∴ x = -1

OR

∴ 5 -x = -6 ⇒ subtract 5 from both sides

∴ -x = -11 ⇒ divide both sides by -1

∴ x = 11

* The solution of I5 - xI = 6 is {-1 , 11}

4- ∵ I6x - 8I + 7 = 5 ⇒ Subtract 7 from both sides

∴ I6x - 8I = -2

- I  I never give negative answer

* The solution of I6x - 8I + 7 = 5 is ∅

5- ∵ Ix + 3I = 12

∴ x + 3 = 12 ⇒ subtract 3 from both sides

∴ x = 9

OR

∴ x + 3 = -12 ⇒ subtract 3 from both sides

∴ x = -15

* The solution of Ix + 3I = 12 is {-15 , 9}

6- ∵ Ix - 3I = -12

- I  I never give negative answer

* The solution of Ix - 3I = -12 is ∅

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3 years ago
For fun question
ZanzabumX [31]
Consider the function f(x)=x^{1/3}, which has derivative f'(x)=\dfrac13x^{-2/3}.

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Can someone help me with this question please?
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Answer:

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Step-by-step explanation:

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Fynjy0 [20]

Marcario should use  4 pounds of macadamia nuts and 8 pounds of almonds.

Explanation

given

cost of macadamia nuts per pound=$9

cost of almond nuts per pound=$5.25

cost of the mixture per pound=$6.5

total pounds of the mixture to be made=12

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solving (1) and (2)

x=4

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