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lora16 [44]
1 year ago
12

20 points

Mathematics
1 answer:
Fantom [35]1 year ago
7 0

Answer:

The value 4.5 is rational and the value 15−−√ is irrational. The sum of 4.5 and 15−−√ has a non-repeating and non-terminating decimal expansion. Therefore, the sum of 4.5 and 15−−√ is irrational. I can't explan but that's the correct Answer

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Samuel and 4 of his friends entered a chili cook-off. The rules allowed them
larisa86 [58]
Each of the 4 friends spent 15 dollars so all you need to do is multiply 4 by 15. 4x15=60
6 0
2 years ago
Read 2 more answers
6a-2(4a-5)=40<br>How do I solve it​
Elza [17]

Answer:

Distribute, then combine like terms, subtract 10 from both sides of the equation, simplify, divide both sides of the equation by the same term, and simplify to get your solution.

Step-by-step explanation:

1.) Distribute

6−2(4−5)=40

6−8+10=40

2.) Combine like terms

6a-8a+10=40

-2a+10=40

3.) Subtract 10 from both sides of the equation

-2a+10=40

-2a+10-10=40-10

4.) Simplify

subtract the numbers

-2a+10-10=40-10

-2a=40-10

subtract the numbers

-2a=40-10

-2a=30

-2a=30

5.) Divide both sides of the equation by the same term

-2a=30

\frac{-2a}{-2} =\frac{30}{-2}

6.) Simplify

cancel terms that are in both the numerator or denominator

\frac{-2a}{-2} =\frac{30}{-2}

a=\frac{30}{-2}

Divide the numbers

a=\frac{30}{-2}

a=-15

a=-15

7.) Solution

a=-15

8 0
3 years ago
The total cost of 4 goldfish and 3 guppies is $29. 3 goldfish and 5 guppoes cost $30. How much does each cost
Aneli [31]

let the goldfish be x and the guppies be y

4x + 3y = 29...equ(1)

3x + 5y = 30...equ(2)

multiplying equation 1 by 5 and equation 2 by 3

20x + 15y = 145...equ(1)

9x + 15y = 90...equ(2)

subtracting equation 2 from 1

11x = 55

∴x = 5

 substituting the value of x into equation

4(5) + 3y = 29

20 + 3y = 29

3y = 9

∴y =3

5 0
3 years ago
50points+brainliest for the one who solved this.It's not a homework but I am curious​
4vir4ik [10]

Answer:

  • 1/xy

Step-by-step explanation:

<u>Simplify the numerator:</u>

  • (2x - y)/(2x + y) + (2x + y)/(3y - 6x) + 8xy/(12x² - 3y²) =
  • (2x - y)/(2x + y) - (2x + y)/3(2x - y) + 8xy/3(2x + y)(2x - y) =
  • [3(2x - y)² - (2x + y)² + 8xy] / [3(2x + y)(2x - y)] =
  • [12x² - 12xy + 3y² - 4x² - 4xy - y² + 8xy] / [3(2x + y)(2x - y)] =
  • [8x² - 8xy + 2y²] / [3(2x + y)(2x - y)] =
  • 2{2x - y)² / [3(2x + y)(2x - y)] =
  • 2(2x - y) / [3(2x + y)]

<u>Simplify the denominator:</u>

  • (4x²y - 2xy²) / (6x + 3y) =
  • 2xy(2x - y) / [3(2x + y)]

<u>Now simplify the remainder of the expression:</u>

  • 2(2x - y) / [3(2x + y)] × [3(2x + y)]/[2xy(2x - y}] =
  • 1/xy
4 0
2 years ago
B is the midpoint of AC, E is the midpoint of BD. If A(-9,-4), C(-1,6), and E(-4,-3), find the coordinates of D
Vadim26 [7]

Answer:

(-3, -7)

Step-by-step explanation:

Let (x_{A,}y_{A}),(x_{B},y_{B}),(x_{C,}y_{C}),(x_{D,}y_{D})(x_{E,}y_{E)} \text{be the coordinates of points A, B, C respectively}\\\\

The midpoint coordinates (x_{M},y_{M}) of any two points (x_{1},y_{1}) and (x_{2},y_{2}) are given by x_{M}=\frac{(x_{1}+x_{2)}}{2} and y_{M}=\frac{y_{1}+y_{2}}{2}

Since B is the midpoint of AC

x_{B}=\frac{(x_{A}+x_{C})}{2}=\frac{(-9+(-1)}{2}=\frac{-9-1}{2}=\frac{-10}{2}=-5

y_{B}=\frac{(y_{A}+y_{C})}{2}=\frac{(-4+6)}{2}=\frac{2}{2}=1

Since E is the midpoint of B and D and we are given the coordinates of E as (-4,-3). it follows that

x_{E}=\frac{x_{B}+x_{D}}{2} = \frac{-4+x_{D}}{2}

Therefore

x_{D}=2x_{E}+4=2(-5)+4=-3

Similarly

y_{E}=\frac{y_{B}+y_{D}}{2} = \frac{1+x_{D}}{2}y_{D}=2y_{E}-1=2(-3)-7=-7

8 0
1 year ago
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