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Yakvenalex [24]
4 years ago
5

Xis normally distributed with mean 1,000 and standard deviation 250. What is the probability that X lies between 800 and 1, 100?

Mathematics
1 answer:
Dominik [7]4 years ago
5 0

Answer:

0.4435

Step-by-step explanation:

Given that :

X is normally distributed:

mean(m) = 1,000

standard deviation (s) = 250

probability that X lies between 800 and 1,100?

Using the relation :

X = 800

Zscore = (x - m) / s

Zscore = (800 - 1000) / 250

Zscore = - 200 / 250

Zscore = - 0.8

P(Z ≤ - 0.8) = 0.2119

X = 1100

Zscore = (x - m) / s

Zscore = (1100 - 1000) / 250

Zscore = 100 / 250

Zscore = 0.4

P(Z ≤ 0.4) = 0.6554

P(Z ≤ 0.4) - P(Z ≤ - 0.8)

0.6554 - 0.2119

= 0.4435

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Please help me solve this. Please don’t give me a link, or it will be reported. Please provide step by step explanations. Thanks
nika2105 [10]

Answer:

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Step-by-step explanation:

Step 1: Get rid of the denominator.

LCD of 4 & 3: 12

Multiply both sides by 12.

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3 years ago
Suppose the time to process a loan application follows a uniform distribution over the range of 8 to 13 days. What is the probab
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Answer: 0.2

Step-by-step explanation:

We know that , the probability density function for uniform distribution is given buy :-

f(x)=\dfrac{1}{b-a}, where x is uniformly distributed in interval [a,b].

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Please mark brainliest.
Have good day :)
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