$\dfrac{\sin x + \cos x}{\cos^2 x - \sin^2 x}\\ \\\\=\dfrac{\sin x + \cos x}{(\cos x + \sin x )\\\\(\cos x - \sin x)}\\\\\\=\dfrac{1}{\cos x - \sin x}$

3 0

2 years ago

Which system is equivalent to

sammy [17]

<u>Answer:</u>

D) 6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11

<u>Step-by-step explanation:</u>

We are given the following two expressions:

$3x^2-4y^2=25$

and

$-6x^2-2y^2=11$

Now if we look at the option D) $6x^2 - 8y^2 = 50
$ and $-6x^2 - 2y^2 = 11$ , we can observe that the earlier part in the given expression is just a simplification of 6x^2 - 8y^2 = 50.

$6x^2 - 8y^2 = 50\\\\2(3x^2-4y^2) = 50\\\\3x^2-4y^2 = \frac{50}{2} \\\\3x^2-4y^2=25$

and the later part $-6x^2 - 2y^2 = 11$ is already the same.

Therefore, the correct answer option is D) 6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11.

6 0

3 years ago

Read 2 more answers

Maristella is constructing an isosceles triangle to use as a model in her Algebra class. The perimeter of her triangle is 24 cm.

Vlada [557]

Isolating s, the equation written in terms of s is:

$s = 12 - 0.5b$

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The equation for the length of the third side, as stated in the problem,("Maristella uses the equation b = 24 – 2s to find b, the length of the triangle's third side") is:

$b = 24 - 2s$