Sure:
90 year old parents : 60 year old children (had kids at 30; very reasonable)
60 year old parents : 40 year old children (had kids at 20; unlikly but possible)
45 year old parents : 30 year old children (had kids at 15; very unlikly but not impossible)
Solution :
Given :
X = the number of boys in a family of four children
Families having four children are chosen randomly.
The gender distribution in the four child family are equally probable.
Thus,
X P(X) CDF
0
= 1/16 
1
= 1/4
2
= 3/8 
3
= 1/4 
4
= 1/16 1
Step-by-step explanation:
Here is the solution...hope it helps:)