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3 years ago

Given the equation 5 + x - 12 = x- 7.

Mathematics

1 answer:

marusya05 [52]3 years ago

8 0

Answer:

Step-by-step explanation:

5 + x - 12 = x- 7 (Add the 5 and -12 to simplify)

x - 7 = x - 7 (notice its the same on both sides of equal sign. Add 7 to both sides)

x = x

solution is all real numbers

Part B

5 - 4 - 12 = -4 - 7

-11 = -11

5 + 0 - 12 = 0 - 7

-7 = -7

5 + 5 - 12 = 5 - 7

-2 = -2

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Change 179km to miles. Type a whole number or a decimal. Round to four decimal places as needed.

atroni [7]

Answer:

179/1.60934 miles then divide to get the whole number/ decimal.

Step-by-step explanation:

A quick search tells me there are 1.60934 km in 1 mile.

To convert from one unit to another there is a super simple method. Set up a fraction with the two values, so in this case 1/1.60934 or 1.60934/1. Which do you use? well it depends which you are tryng to convert.

1.60934/1 has the units km/miles so since miles is on the bottom we would use it to convert miles. That's hat you have to look at, what is in the denominator. Since we are converting 179 km we want km on the bottom.

So we use 1/1.60934 instead because the units are miles/km. now you just multiply the 179 by the fraction. so the answer is 179/1.60934 miles.

Now it says we need a whole number of decimal, can you handle the division?

7 0

3 years ago

Video game system and several games are sold for $664. The cost of the games is 3 times as much is a cost in system. Find the co

Ede4ka [16]

Answer:

games=$483

system=$161

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Tom and Kathy want to borrow $35,000 in order to build an addition to their home.

Novosadov [1.4K]

Answer:

I think its C you can hate how much you want if I'm wrong im more of a no tester when I get an answer i check but not online

Step-by-step explanation:

7 0

3 years ago

Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are

Svetlanka [38]

Answer:

(a) Number of sets B given that

A⊆B⊆C: 2¹⁰. (That is: A is a subset of B, B is a subset of C. B might be equal to C)
A⊂B⊂C: 2¹⁰ - 2. (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

Let $x_1, x_2, \cdots, x_{20}$ denote the 20 elements of set X.

Let $x_1, x_2, \cdots, x_{10}$ denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain $x_1, x_2, \cdots, x_{10}$ .

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from $x_1, x_2, \cdots, x_{20}$ .

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves $2^{10} -2 = 1024 - 2 = 1022$ possibilities.

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's $2^{20} = 1048576$ possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only $2^{20} - 2^{10}$ possibilities left.

5 0

3 years ago

Sums of series, Maths. Any help appreciated.

Andrej [43]

Answer:

Step-by-step explanation:

Well, a series in math is simply the sum of the various numbers, or elements of a sequence. For example, to make a series from the sequence of the first five positive integers 1, 2, 3, 4, 5, just add them up. So, 1 + 2 + 3 + 4 + 5 = 15 is a series.

that all what i know i am really sorry bro but that is what i understand !

7 0

3 years ago